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Novosadov [1.4K]
4 years ago
5

A carpet sells for $28.99 a square yard. What is the price of the carpet per square meter?

Chemistry
2 answers:
9966 [12]4 years ago
7 0

It is given that the price of the carpet is $ 28.99 per square yard

Step 1: Convert square yard to square meter

1 square yard = 0.836 square meter

Step 2: Calculate the cost/square meter

Now based on the relation in step (1) we can write

0.836 square meter of carpet costs $ 28.99

Therefore the cost of 1 square meter of the carpet would be

= $ 28.99 * 1 sq meter/0.836 sq meter

= $ 34.68

Vikentia [17]4 years ago
5 0

Answer:

$34.68 per square meter.

Explanation:

A carpet sells for $28.99 a square yard.

We have to calculate the price of the carpet per square meter.

1 square yard = 0.836 square meters

The carpet sells for $28.99 for 0.836 meter²

Therefore, the cost of the carpet for 1 square meter =  \frac{28.99}{0.836}

                                                                        = $34.677 ≈ $34.68

The price of the carpet per square meter is $34.68

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Zolol [24]

Answer:

6.38

Explanation:

line up the decimals

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2.60

+ 3.78

= 6.38

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6 + 7 = 13; write 3 and carry the one over above the 2 in 2.60

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I tried my best to show it through text.

4 0
3 years ago
Solve these Please. (15 points)
Ghella [55]

Answer:

1) 4Fe + 3O2 → 2Fe2O3

2) H2 + Cl2 → 2HCl

3) 2Ag + H2S → Ag2S + H2

4) CH4 + 2O2 → CO2 + 2H2O

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3 0
3 years ago
How many liters of ammonia (NH3), at 3.2 atm and 23C, must be used to produce of 2.65 grams of calcium hydride (CaH2). 6 Ca(s)
7nadin3 [17]

Answer:

The answer to your question is    V = 0.32 L

Explanation:

Data

Volume of NH₃ = ?

P = 3.2 atm

T = 23°C

mass of CaH₂ = 2.65 g

Balanced chemical reaction

               6Ca  +  2NH₃   ⇒   3CaH₂  +  Ca₃N₂

Process

1.- Convert the mass of CaH₂ to moles

-Calculate the molar mass of CaH₂

 CaH₂ = 40 + 2 = 42 g

                             42 g ------------------ 1 mol

                              2.65 g --------------  x

                              x = (2.65 x 1)/42

                              x = 0.063 moles

2.- Calculate the moles of NH₃

                     2 moles of NH₃ --------------- 3 moles of CaH₂

                      x                        --------------- 0.063 moles

                                x = (0.063 x 2) / 3

                                x = 0.042 moles of NH₃

3.- Convert the °C to °K

Temperature = 23°C + 273

                      = 296°K

4.- Calculate the volume of NH₃

-Use the ideal gas law

              PV = nRT

-Solve for V

                V = nRT / P

-Substitution

                V = (0.042)(0.082)(296) / 3.2

-Simplification

               V = 1.019 / 3.2

-Result

               V = 0.32 L

7 0
3 years ago
A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
Andre45 [30]

Answer:

* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

* m=2.46m

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

7 0
3 years ago
Calculate the percentage composition of each element in calcium hydroxide
sp2606 [1]

Answer:

54.1 % Ca, 43.2 % O, 2.7% H

Explanation:

Molecular formula for calcium hydroxide is Ca(OH)₂

As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.

1 mol of hydroxide weighs 74.08 g

1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca

2 moles of O therefore 32g are O

2 moles of H therefore 2 g are H

Percentage composition is known as (Mass of element/Total mass) . 100

  • (40.08 / 74.08) . 100 = 54.1 %
  • (32 / 74.08) . 100 = 43.2 %
  • (2 / 74.08) . 100 = 2.7%
6 0
3 years ago
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