Answer:
a) 0.100 M
b) 0.395 M
Explanation:
a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution
We will use the following expression for molarity.
[NaOH] = moles of solute / liters of solution
[NaOH] = 0.200 mol/2.00 L = 0.100 M
b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution
We will use the following expression for molarity.
[NaCl] = mass of solute / molar mass of solute × liters of solution
[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M
Any substance that contains only one type of atom is referred to as an element.Elements are the "building blocks" of everything. Each element only contains one type of atom. If substances carry more than one type of atom, then they are compounds.
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Answer:
I think 4 I got it right on edg but i duno if its the same
Explanation:
The new volume is 2.4 L
<u><em> calculation</em></u>
The new volume is calculated using Boyle's law formula
That is P₁V₁=P₂V₂
where,
p₁ = 802 torr
V₁ = 12.0 l
P₂ = 4010 torr
V₂=?
make V₂ the subject of the formula by diving both side of equation by P₂
V₂ = P₁V₁/P₂
V₂ is therefore = {(12.0 l × 802 torr) 4010 torr} = 2.4 L
The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
moles NaOH = c · V = 0.2423 mmol/mL · 32.23 mL = 7.809329 mmol
moles H2SO4 = 7.809329 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.9046645 mmol
Hence
[H2SO4]= n/V = 3.9046645 mmol / 37.21 mL = 0.1049 M
The answer to this question is [H2SO4] = 0.1049 M
