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Dafna11 [192]
3 years ago
6

Please answer this X+2y=6 3x-y= -10

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0
3x-y=-10
y=3x+10
so the equation “x+2y=6” is “x+2(3x+10)=6” so we have:
x+6x+20=6
7x=6-20
7x=-14
x=-14/7=-2
to get y we can replace x with its value “-2” in the equation”y=3x+10” so we have:
y=3(-2)+10=-6+10=4
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How many whole servings of 3/4 cups are in 31/2 cups of ice cream?
IrinaVladis [17]
20 servings :) You multiply the 31/2 by 2 then divide 62 by 3 and thats your answer
6 0
3 years ago
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If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b
MAXImum [283]

We have

\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}

So

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0

as required.

3 0
3 years ago
What is the product? 6(x^2-1) times 6x-1 over 6(x+1)
sergejj [24]

(36x^3-36x-1)/6x+6 or 6x^2-6x+(-1/6x+6)

8 0
3 years ago
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W+3=w+6 please show step by step
Stels [109]

w +  3 = w + 6 \\ w - w + 3 = w - w + 6 \\ 3 = 6
Since 3 does not equal 6, therfore the answer is no solution.
8 0
3 years ago
If a girl read 3/8 of a chapter book and another girl read 3/6 of a chapter book which girl read more pages
fredd [130]

Answer:

The girl which read 3/6 of a chapter book read more pages than the other girl.

Step-by-step explanation:

We need to compare between \frac{3}{8} \ and \ \frac{3}{6}

so, the denominator of both fractions should be the same number

Factor of 6 = 1 * 2 *          * 3

Factor of 8 = 1 * 2 * 2 * 2

-------------------------------------------

The common denominator  = 1 * 2 * 2 * 2 * 3 = 24

\frac{3}{8} = \frac{3*3}{3*8} =\frac{9}{24} \\\frac{3}{6} = \frac{4*3}{4*6} =\frac{12}{24}

Then compare between \frac{9}{24} \ and \frac{12}{24}  \\

So, the fraction of the great numerator will be the great fraction

\frac{12}{24}  > \frac{9}{24}

∴ \frac{3}{6} > \frac{3}{8}

==================================================

<u>Another solution:</u>

Convert both fractions to decimal:

3/8 = 0.375

3/6 = 0.5

0.5 > 0.375

===================================================

<u>Third Solution: </u>

As the numerators are equal

The fraction of least denominator is the great fraction

So, 3/6 > 3/8

3 0
3 years ago
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