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Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has

RUDIKE [14]

Answer:

1)

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) = 0.025 - 0.015 = 0.01

THEREFORE the Bivariate Table;

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3) probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% = 0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0

4 years ago

A car traveled at a constant speed. The graph shows how far the car traveled, in miles, during a given amount of time, in hours.

snow_tiger [21]

Answer:

Step-by-step explanation:

A car traveled at a constant speed as shown in the graph.

Distance traveled is on the y-axis and duration of travel on the x-axis.

Point A(3.5, 210) shows,

Distance traveled = 210 miles

Time to travel = 3.5 hours

So the point (3.5, 210) shows the distance traveled by the car in 3.5 hours is 210 miles.

Slope of the line = speed of the car = $\frac{\text{Distance traveled}}{\text{Time}}$

= $\frac{210}{3.5}$

= 60 mph

Now we will find the speed of the car at another point B(1, 60).

If the speed of car is same as the point B as of point A, point B will lie on the graph.

Speed of the car at B(1, 60) = $\frac{\text{Distance traveled}}{\text{Time}}$

= $\frac{60}{1}$

= 60 mph

Hence, we can say that point B(1, 60) lies on the graph.

8 0

3 years ago

Identify the vertex, focus , axis of symmetry and directrix(??+1)2 =8(x-3)

melisa1 [442]

Answer:

70

Step-by-step explanation:

5 0

3 years ago

I WILL MARK BRAINLIEST

Mazyrski [523]

Answer:

-6, -5, -4, -3, and -2

n≥-6

Step-by-step explanation:

Multiply both sides by 2

n≥-6

so the values that make this true are -6, -5, -4, -3, and -2

8 0

3 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

PolarNik [594]

Answer:

by mid point formula,

$\frac{9+x}{2}=11 \\ \implies x= 13$

similarly, $\frac{1+y}{2}=4 \\ \implies y,= 7$

endpoint is (13,7)

8 0

3 years ago