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3 years ago

Need help on this

Mathematics

1 answer:

Stolb23 [73]3 years ago

4 0

15.12m2 just finished the test

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Find the volume of the prism.

gtnhenbr [62]

Answer:

66 $cm^{3}$

Step-by-step explanation:

Vol = Bh where B is the area of the base and h is the distance between the bases (height)

The base is a right triangle and has an area of

B = 1/2bh = 1/2(4)(3) = 6

h = 11

V = 6(11) = 66 $cm^{3}$

4 0

3 years ago

We study proofs in computing because it helps us understand data structures

alisha [4.7K]

Answer:

false

Step-by-step explanation:

we study proofs in computing because it helps us to understand the mathematical computation. With the help of proofs in computing it is very easy to understand all the mathematical computation but in given statement it is given that it helps us to understand data structure so it is a false statement.

8 0

3 years ago

The polynomial of degree 4, P(x) has a root of multiplicity 2 at x = 4 and roots of multiplicity 1 at x = 0 and x = - 3 3. It go

NemiM [27]

Answer:

The complete polynomial will be:

$P(x)=\frac{7}{10}x(x+3)(x-4)^2$

Step-by-step explanation:

If one root has multiplicity 2 at x = 4, the factor can write as:

$(x-4)^{2}$ (1)

Now, another root has a multiplicity 1 at x=0 and x=-3, then the factors will be:

$x$ (2)

$(x+3)$ (3)

Putting (1),(2), and (3) together we can construct the polynomial.

$P(x)=Cx(x+3)(x-4)^2$ (4)

C is a constant value

We need to use the point (5, 28) to find the constant C. 5 is the x value and 28 is the P(x) value. Replacing these values into the (4) equation:

$28=C5(5+3)(5-4)^2$

$28=C5(8)(1)^2$

$28=40C$

$C=\frac{28}{40}$

$C=\frac{7}{10}$

Finally, the complete polynomial will be:

$P(x)=\frac{7}{10}x(x+3)(x-4)^4$

I hope it helps you!

8 0

3 years ago

What is 16.437 rounded to the nearest tenth

Hunter-Best [27]

16.4 to nearest tenth

3 0

4 years ago

Is the relation {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)} a function? Explain. Type your answer below

Blizzard [7]

Yes.

This is because all x values have only one corresponding y value. If an x value were to have 2 different y values, the relation would not be a function.

8 0

4 years ago