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7nadin3 [17]
3 years ago
12

The ravens scored 13 more than three times number points that the bengals scored in their last game. If the ravens scored 40 poi

nts how many points did the bangals score
Mathematics
1 answer:
katrin2010 [14]3 years ago
5 0

The score of Raven is 9 points

<em><u>Solution:</u></em>

Let the point scored by bangal be"x"

Score of Raven = 40 points

Given that,

The ravens scored 13 more than three times number points that the bangals scored in their last game

Score of raven = 13 + 3(score of bangal)

40 = 13 + 3x

Solve the above equation for x

3x = 40 - 13

3x = 27

x = 9

Thus the score of Raven is 9 points

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The graph shown below can be described using the equation y=Acos(bx)=k. Which of the following is the value of B +K.

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3 0
2 years ago
Jim and bill each invest $15,000 into savings accounts that earn 3.5% interest. Jims account earns simple interests and bills ac
Svet_ta [14]

Answer:

Bill will earn more interest

He will earn $ 20,448.67 from his investment

Step-by-step explanation:

Firstly let us calculate Jim's earnings based on simple interest

A = P(1 + rt)

Calculation:

First, converting R percent to r

a decimal

r = R/100 = 3.5%/100 = 0.035 per year.

Solving our equation:

A = 15000(1 + (0.035 × 25)) = 28125

A = $28,125.00

The total amount accrued, principal plus interest, from simple interest on a principal of $15,000.00 at a rate of 3.5% per year for 25 years is $28,125.00 for Jim

Now let's us calculate bill's investment based on compound interest

Equation

A = P(1 + r)^t

A=15000(1+0.035)^25

A=15000(1.035)^25

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We see that Bill will earn

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4 0
2 years ago
Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct
Nana76 [90]

Answer:

Fx=\frac{5\pm\sqrt{25+24} }{6}

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

ax^2+bx+c

Where:

a\neq 0

The roots of this equation can be found using the quadratic formula, which is given by:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

So:

y(x)=3x^2-5x-2=0

As you can see, in this case:

a=3\\b=-5\\c=-2

Using the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}

Therefore, the answer is:

Fx=\frac{5\pm\sqrt{25+24} }{6}

4 0
3 years ago
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