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Sliva [168]
3 years ago
11

Michaela paid $690 wholesale for mirrors that cost $933 retail. Calculate the percent decrease in price. 

Mathematics
2 answers:
aliina [53]3 years ago
8 0
A) $933 - $690 = $243
b) $243 ÷ $933 = 0.2604
c) 0.2604 x 100 = 26.04 %

Decrease was about 26.04 %
PIT_PIT [208]3 years ago
3 0
The bargain price she was given was 690/933 = 73.95 percent of retail.

The rest ... 26.05 percent ... was her discount.
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In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006. What was Daniel's rate of growth over this period of his
andreyandreev [35.5K]

Answer:

he grows by 5 cm every year between 1999 and 2006

Step-by-step explanation:

This is a arithmetic progression problem with the formula;

T_n = a + (n - 1)d

We are told that In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006.

Thus;

a = 146

d = 2006 - 1999 = 7

Thus;

176 = 146 + (7 - 1)d

176 - 146 = 6d

30 = 6d

d = 30/6

d = 5 cm

Thus, he grows by 5 cm every year between 1999 and 2006

3 0
3 years ago
Jillian bought 1/2 pound of turkey and 1 1/3 pounds of cheddar cheese at the store.both items are on sale $6 per pound.how much
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10 dollars is ther answer
8 0
3 years ago
P;EASE HELP!!!!!  Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end
Marrrta [24]
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7 0
4 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
3 years ago
1.) Which of the following expressions is the difference of two terms?
Step2247 [10]

Answer:

1.a

2.a

3.d

4.c

5.c

Step-by-step explanation:

sana makatulung po

8 0
3 years ago
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