The answer is the third one need any more help let me know
Answer:
3.2. The decimal point moves left once because there's only one 0
Step-by-step explanation:
Answer:
Step-by-step explanation:
Simplifying
-3a + 8 = 2z + -12
Reorder the terms:
8 + -3a = 2z + -12
Reorder the terms:
8 + -3a = -12 + 2z
Solving
8 + -3a = -12 + 2z
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + -3a = -12 + -8 + 2z
Combine like terms: 8 + -8 = 0
0 + -3a = -12 + -8 + 2z
-3a = -12 + -8 + 2z
Combine like terms: -12 + -8 = -20
-3a = -20 + 2z
Divide each side by '-3'.
a = 6.666666667 + -0.6666666667z
Simplifying
a = 6.666666667 + -0.6666666667z
Answer:
The correct answer B) The volumes are equal.
Step-by-step explanation:
The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

which when evaluated gives 4pi/3.
Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.