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3 years ago

I need help ASAP plllzz yall

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

6 0

1. 25n + 0.08 (25n) + 17, simplified is 27n + 17

2. 6c + (0.05 + 0.20) (6c) - 10, simplified is 7.5c - 10

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The radii of two right circular cylinders are in the ratio 3 : 4 and their heights are in the ratio 1 : 2. Calculate the ratio o

bezimeni [28]

Answer:

18.852:50.272

Step-by-step explanation:

Step one:

given

The radii of two right circular cylinders are in the ratio 3 : 4

r1= 3

r2= 4

Their heights are in the ratio 1 : 2

h1= 1

h2= 2

Step two:

The expression for the curve surface area is

CSA= 2πrh

CAS1= 2πr1h1

CAS1= 2*3.142*3*1

CAS1= 18.852

CAS2= 2πr2h2

CAS2= 2*3.142*4*2

CAS1= 50.272

The ratio of their curved surface areas

=18.852:50.272

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3 years ago

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kykrilka [37]

The answer is (1,4) and (-1,-4)

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3 years ago

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STALIN [3.7K]

I have a good record of guessing the right one so I would say #1.

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3 years ago

Y as a function of x graph

Ann [662]

Answer:

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Step-by-step explanation:

7 0

3 years ago

Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).

Marina86 [1]

Given:

The given equation is:

$y=-4x+3$

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

$y=mx+b$

Where, m is slope and b is y-intercept.

We have,

$y=-4x+3$

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

$m\times (-4)=-1$

$m=\dfrac{-1}{-4}$

$m=\dfrac{1}{4}$

The slope of required line is $m=\dfrac{1}{4}$ and it passes through the point (4,-1). So, the equation of the line is:

$y-(-1)=\dfrac{1}{4}(x-4)$

$y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}$

$y=\dfrac{1}{4}x-1-1$

$y=\dfrac{1}{4}x-2$

Therefore, the equation of the required line is $y=\dfrac{1}{4}x-2$ .

5 0

2 years ago