Answer:
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
Step-by-step explanation:
given that after comparing response times between the audio and picture portions of the MIT test, the t-test resulted in a t-value of 2.97.
test statistic t = 2.97
Sample size n =250
Critical value of t at 95% is 1.96
We find that test statistic absolute value is greater than 1.96
So p value would be less than 0.05
This implies that null hypothesis stands in the rejected region.
So reject null hypothesis would be correct conclusion. Sample size cannot be said to be small as more than 30 itself is a good sample size.
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
Answer:
48v - 16x + 32
Step-by-step explanation:
A. figure ABCD is similar to figure A'B'C'D'
Express √3 + i in polar form:
|√3 + i| = √((√3)² + 1²) = √4 = 2
arg(√3 + i) = arctan(1/√3) = π/6
Then
√3 + i = 2 (cos(π/6) + i sin(π/6))
By DeMoivre's theorem,
(√3 + i)³ = (2 (cos(π/6) + i sin(π/6)))³
… = 2³ (cos(3 • π/6) + i sin(3 • π/6))
… = 8 (cos(π/2) + i sin(π/2))
… = 8i
147 63 82 101 155 160 175 92 116 138 74 93 110 162 154 105 97
The frequency to her third group is 80 - 99.
