-2 is the answer, because it is the answer to the question you are asking
Answer:
factor of 100 more heat loss in actual
Step-by-step explanation:
Given:
- Length of the cube = 6 in
- Length of another cube = 12 in
- Actual submarine size = 70 ft
- Scale model = 7-ft
Find:
Relate the heat loss of a 70-ft submarine to that of a 7-ft scale model. Suppose you are interested in the amount of energy needed to maintain a con- stant internal temperature in the submarine.
Solution:
- The surface area of the small cube is 6 · 36.
- Scaling the sides by k means the new surface area is 6 · (6k · 6k) = k
^2*
(6 · 36).
- Therefore, double the lengths increases the surface area 4 times (and so there will also be 4 times as much heat loss).
- Now consider two irregularly shaped objects, such as submarines. If we
can measure heat loss from a 7 foot scale model, heat is lost from a 70 foot sub is:
- An increase by a factor of 10 will mean that heat loss (which is proportional to surface area) increases by a factor of 10^2 = 100
Answer: $250
Step-by-step explanation: To calculate the past year`s tax, divide this year tax to 1.15.
$ = 287.50 / 1.15 = 250
Answer:
kool
Step-by-step explanation:
You need to select any numbers that are greater than 28.
If you entered the number 27 in the missing space, you would have two numbers that are equal to each other. However, we want the right side to be larger so we need to select anything larger than 27.