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tester [92]
3 years ago
11

Please help my assignment is missing and I really need to finish it.

Mathematics
2 answers:
Alenkinab [10]3 years ago
7 0
The answer is D. Hope this helps
photoshop1234 [79]3 years ago
4 0

Answer: it is D

Step-by-step explanation:

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Will give brainliest! please answer!
Montano1993 [528]

Answer:

Step-by-step explanation:

933  +  the  cost <=1500

933+ c <=1500

3 0
3 years ago
Read 2 more answers
g Nationwide, a certain disease occurs only a small proportion of people (.000215). A certain town has 74,000 residents. Use the
Andrei [34K]

Answer:

The probability that the town has 30 or fewer residents with the illness = 0.00052.

Step-by-step explanation:

So, we have the following set of data or information or parameters given from the question above and they are; the number of people living in that particular society/community/town = 74,000 residents and the proportion of people that the diseases affected = .000215.

The first step to do is to determine the expected number of people with disease. Thus, the expected number of people with disease = 74,000 × .000215 = 15.91.

Hence, the probability that the town has 30 or fewer residents with the illness = 1.23 × 10^-7 × 15.91^30/ 2.65253 × 10^-32 = 0.00052.

Note the formula used in the calculating the probability that the town has 30 or fewer residents with the illness =  e^-λ × λ^x/ x!

8 0
3 years ago
Can somebody help???
Oduvanchick [21]

Answer:

first box - 2.10

second box - 2.14

4 0
2 years ago
Read 2 more answers
In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi
Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n  = 50

sample mean \overline x = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

X \sim N ( \mu \sigma)

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})

P(X>140) = 1 - P( Z\leq0.42)

From z tables,

P(X>140) = 1 - 0.6628

P(X>140) = 0.3372

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

Y \sim Binomial (np)

Y \sim Binomial (50,0.3372)

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49}  + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +...  + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}

P(Y ≥ 15) = 0.763

7 0
3 years ago
Write an equation for each translation of y = |x|
nata0808 [166]
If you want to write an equation for an absolute value function this is the parent function y=a|x-h|+k.

In order to write an equation that is 16.5 units right you would do this:

y=|x-16.5|
If you are moving units left the number -16.5 would become 16.5

Remember when you are moving that the number inside is always the opposite sign of where you are moving 

Here is the answer:
y=|x-16.5|
Hope This Helps!
3 0
3 years ago
Read 2 more answers
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