Answer
Find out the original side length of the square .
To prove
Let us assume that the original length of the square be x.
Formula

As given
The dimensions of a square are altered so that 8 inches is added to one side while 3 inches is subtracted from the other.
Length becomes = x + 8
Breadth becomes = x -3
The area of the resulting rectangle is 126 in²
Put in the formula
(x + 8) × (x - 3) = 126
x² -3x + 8x -24 = 126
x ²+ 5x = 126 +24
x² + 5x - 150 = 0
x² + 15x - 10x - 150 = 0
x (x + 15) -10 (x +15) =0
(x + 15)(x -10) =0
Thus
x = -15 , 10
As x = -15 (Neglected this value because the side of the square cannot be negative.)
Therefore x = 10 inches be the original side of the square.
25/28 - 2/7
it doesn’t need to be solved because it asked for an expression and not an equation, so no equal sign either
Y=a(x-h)^2+k
-5=a(1-0)^2+2
-5=a+2
-3=a
y=-3x^2+2
Using PEMDAS
P = 1x1+9x(0.01)+1x(0.001)
E = no change
M = 1+0.09+0.001
D = no change
A = 1.091
S = no change
final answer is 1.091
Answer:
-13
Step-by-step explanation:
(7−15−3+5−7)⋅1
Subtract 15 from 7 to get −8.
(−8−3+5−7)×1
Subtract 3 from −8 to get −11.
(−11+5−7)×1
Add −11 and 5 to get −6.
(−6−7)×1
Subtract 7 from −6 to get −13.
−13