The value of x in tan(x)=sin38° is 31.6 and the value of x in cosec(x+10°)=1.345 is 38.0
<h3>How to solve the trigonometry ratios?</h3>
The equations are given as:
tan(x)=sin38°
cosec( x+10°)=1.345
In tan(x)=sin38°, we have:
tan(x)=0.6157
Take the arc tan of both sides
x = 31.6
Also, we have:
cosec(x+10°)=1.345
Take the inverse of both sides
sin(x+10°) = 0.7434
Take the arc sin of both sides
x+10 = 48.0
Subtract 10 from both sides
x = 38.0
Hence, the value of x in tan(x)=sin38° is 31.6 and the value of x in cosec(x+10°)=1.345 is 38.0
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Answer:
Step-by-step explanation:
let the side of outer square=2x
then x²+x²=(20√2)²
2x²=800
x²=400
x=√400=20 in
2x=2×20=40 in
area of outer square=40²=1600 in²
area of inner square=(20√2)²=800 in²
area of shaded region A=1600-800=800 in²
Answer:
Step-by-step explanation:
y=1/5+0 is the answer to your problem I very much believe
Answer: y= - 4x+18
Step-by-step explanation:
Equation: y=mx+b
***remember: b is the y-intercept and m is the slope.
m=
3= x1
2= x2
6= y1
10=y2
m=
= 
= -4
m=-4
Now we have y=-4x+b , so let's find b.
You can use either (x,y) such as (3,6) or (2,10) point you want..the answer will be the same:
(3,6). y=mx+b or 6=-4 × 3+b, or solving for b: b=6-(-4)(3). b=18.
(2,10). y=mx+b or 10=-4 × 2+b, or solving for b: b=10-(-4)(2). b=18.
Equation of the line: y=-4x+18
