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satela [25.4K]
2 years ago
5

Find the equation of the line through the points (9,6) and (2,5).

Mathematics
1 answer:
storchak [24]2 years ago
3 0
Slope = 1/7
y=mx+b
y=x/7+33/7


Mark brainliest please
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Find the area of the figure. (Sides meet at right angles.)
daser333 [38]

Answer:

48m squared

Step-by-step explanation:

- cut the problem in half horizontally

you get two squares one square is 4 by 4 and the other 8 by 4

4 times 4=16 8 times 4=32  32+16=48

6 0
2 years ago
Write a sequence of transformation that maps quadrilateral ABCD onto quadrilateral A. B. C. D IN THE PICTURE
Mice21 [21]

Answer:

The sequence of transformation is reflected across the y-axis and translated 2 units down

Step-by-step explanation:

Lets revise some transformation

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) translate h units to the right

∴ Its image is (x + h , y)

- If point (x , y) translate h units to the left

∴ Its image is (x - h , y)

- If point (x , y) translate k units up

∴ Its image is (x , y + k)

- If point (x , y) translate k units down

∴ Its image is (x , y - k)

* Now lets solve the problem

∵ The vertices of figure ABCD are:

  A (-1 , 3) , B (1 , 0) , C (2 , 3) , D (1 , 4)

∵ The vertices of figure A"B"C"D" are:

  A" (1 , 1) , B" (-1 , -2) , C" (-2 , 1) , D" (-1 , 2)

* Lets compare between ABCD and A"B"C"D"

∵ All x-coordinates has opposite signs

  -1 ⇒ 1 , 1 ⇒ -1 , 2 ⇒ -2 , 1 ⇒ -1

∴ The ABCD is reflected across the y-axis

∵ All y-coordinates subtracted by 2

 3 ⇒ 1 , 0 ⇒ -2 , 3 ⇒ 1 , 4 ⇒ 2

∴ The ABCD is translated 2 units down

* The sequence of transformation is reflected across the y-axis

  and translated 2 units down

5 0
3 years ago
Pls help I need this I’m begging you
Stells [14]

Answer:

Option H

Step-by-step explanation:

y = 3x - 4

this is the correct answer.

6 0
2 years ago
Read 2 more answers
If f x equals x -3 + g x equals 1 - x 2 - 9 find ( f og) (x and give any restrictions on its domain
evablogger [386]
\begin{gathered} f(x)=x-3 \\ g(x)=\frac{1}{x^2-9} \\ (\text{fog)(x)}=\frac{1}{x^2-9}-3 \end{gathered}

the denominator cannot be zero, because the division by zero is not defined, therefore:

\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}

Therefore the domain of (f o g)(x) is:

D\colon(-\infty,-3)\cup(-3,3)\cup(3,\infty)

3 0
1 year ago
Jason spent $46.42 on dinner at hello tokyo. he also spent $21.05 on gas for the car. if his bank account had $60.00, what is hi
AleksandrR [38]

It would be: $60.00 - ($46.42+$21.05)

$60.00 - $67.47 = -$7.47

4 0
2 years ago
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