The best answer I can think of is that a line doesn't have a point where it starts or stops, but instead goes on forever, unlike a ray which has a start or end point but not the other, and a line segment which has a start and stop point. Hope this helps!
Given that ABC is a right triangle.
The length of AC = 10 and AB = 17
We need to determine the m∠B
<u>The measure of ∠B:</u>
The side opposite to ∠B is AC and the hypotenuse of the triangle is AB
The m∠B can be determined using the trigonometric identity,

where
and 
Substituting, we get;

Substituting the values, we get;


Taking
on both sides of the equation, we have;


Rounding off to the nearest tenth, we get;

Hence, the measure of ∠B is 36.0°
Answer:
26 cm²
Step-by-step explanation:
The area of the rectangle whose dimensions are shown at the right and bottom is ...
(6 cm)(7 cm) = 42 cm²
The figure is smaller than that by the area of the space whose dimensions are shown at the right and in the middle left:
(4 cm)(4 cm) = 16 cm²
The figure area is then the difference ...
42 cm² - 16 cm² = 26 cm²
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<em>Alternate solution</em>
Draw a diagonal line between the lower right inside corner and the lower right outside corner. This divides the figure into two trapezoids.
The trapezoid at lower left has bases 7 and 4 cm, and height 6-4 = 2 cm. Its area is ...
A = (1/2)(b1 +b2)h = (1/2)(7 + 4)(2) = 11 . . . . cm²
The trapezoid at upper right has bases 6 cm and 4 cm and height 3 cm. Its area is ...
A = (1/2)(b1 +b2)h = (1/2)(6 + 4)(3) = 15 . . . . cm²
Then the area of the figure is the sum of the areas of these trapezoids, so is ...
11 cm² + 15 cm² = 26 cm²
_____
<em>Comment on other alternate solutions</em>
There are many other ways you can find the area of this figure. It can be divided into rectangles, triangles, or other figures of your choice. The appropriate area formulas should be used, and the resulting partial areas added or subtracted as required.
You can also let a geometry program find the area for you. (It is 26 cm².)