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Flura [38]
3 years ago
5

I NEED HELP I’ve been stuck on this for a while now and I don’t get it I tried answering this question many times but I can’t ca

n I please get help please
Answers

A) the relationship is linear; y-5= -4/5 (x-1)

B) the relationship is linear; y-1=4/5(x-5)

C) the relationship is linear; y-5=5/4(x-1)

D) the relationship is not linear

Mathematics
1 answer:
Monica [59]3 years ago
3 0
Substitute each x and the respecting y to the equation
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Find x and y part 4 for these problems​
Dvinal [7]

Answer:

Step-by-step explanation:

3) Sin30 = 11/x

x = 11/Sin30 = 11/0.5

x = 22

Tan 30 = 11/y

y = 11/tan30 = 11/0.5774

y = 19.1

4) Sin30 = 6/x

x = 6/Sin30 = 6/0.5

x = 12

Tan 30 = 6/y

y = 6/tan30 = 6/0.5774

y = 10.39

5) Sin45 = 9√2/y

y = 9√2/Sin45 = 9√2/(√2/2) =

9√2 × 2/√2 = 18

x = 18

Tan 45 = 9√2/x

x = 9√2/Tan 45 = 9√2/1

x = 9√2

6)

Sin60 = 9/x

x = 9/Sin60 = 9/0.866

x = 10.39

Tan 60 = 9/y/2 = 18/y

1.7321 = 18/y

y = 18/1.7321

y = 10.39

6 0
3 years ago
Martin would like to start training to run a marathon. The first week he runs a total of 15 miles. He would like to run 0.3 more
anygoal [31]

Answer: 15.3 miles

Step-by-step explanation:

From the question, we are informed that Martin would like to start training to run a marathon and that first week he runs a total of 15 miles.

We are further told that he would like to run 0.3 more miles each week than the week before. There, the number of miles that Martin will run the second week will be:

= 15 miles + 0.3 miles

= 15.3 miles

3 0
3 years ago
Plot the x- and y-intercepts to graph the equation. y=−x−5
Natasha_Volkova [10]
X-intercept would be (-5,0)

and the y-intercept would be (0,-5)


5 0
3 years ago
Read 2 more answers
What is the midpoint of the line segment with endpoints (–5.5, –6.1) and (–0.5, 9.1)?
astraxan [27]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{-5.5}~,~\stackrel{y_1}{-6.1})\qquad 
(\stackrel{x_2}{-0.5}~,~\stackrel{y_2}{9.1})
\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}~~~ ,~~~ \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-0.5-5.5}{2}~~,~~\cfrac{9.1-6.1}{2} \right)\implies \left( \cfrac{-6}{2}~~,~~\cfrac{3}{2} \right)\implies \left(-3~,~1\frac{1}{2}  \right)
5 0
3 years ago
Please help, thanks.
Svetllana [295]

\text{Apply Pythagorean theorem,}\\ \\~~~~~~12^2 = 3^2 + h^2\\\\\implies h^2 = 12^2 -3^2\\\\\implies h^2 = 144-9\\\\\implies h^2 = 135\\\\\implies h = \sqrt{135}\\\\\implies h = 3\sqrt{15}\\\\\implies h \approx 11.62

6 0
2 years ago
Read 2 more answers
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