I NEED HELP I’ve been stuck on this for a while now and I don’t get it I tried answering this question many times but I can’t ca
n I please get help please
Answers
A) the relationship is linear; y-5= -4/5 (x-1)
B) the relationship is linear; y-1=4/5(x-5)
C) the relationship is linear; y-5=5/4(x-1)
D) the relationship is not linear
Answers
A) the relationship is linear; y-5= -4/5 (x-1)
B) the relationship is linear; y-1=4/5(x-5)
C) the relationship is linear; y-5=5/4(x-1)
D) the relationship is not linear
1 answer:
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Arc length = 2
r * Θ/360 = d * Θ/360
so...
If we take pi to be 3.14,
Arc length = 2(3.14)(6) * 98/360
= 37.68 * 98/360 = 10.26 cm
so...
If we take pi to be 3.14,
Arc length = 2(3.14)(6) * 98/360
= 37.68 * 98/360 = 10.26 cm
Answer:
Step-by-step explanation:
Given that the plane passes through (1,3,3)
Also the plane contains the line x(t)=3t,y(t)=2t,z(t)=4+3t.
This means all points lying in this line will also lie in the plane.
Find out two points on this line.
First point: Let t =0. Point is (0,0,4)
Next point : Let t = 1: Point is (3,2,7)
Now we have 3 non collinear points (0,0,4) (3,2,7) and (1,3,3) lying on the plane.
Equation of the plane is
Simplify to get
x(-2-9)-y(-3-3)+(z-4)(9-2)=0
i.e -11x+6y+7z-28 =0
11x-6y-7z+28 =0 is the equation of the plane.