1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olya-2409 [2.1K]
3 years ago
8

78.03 / 1.008 Sig Fig

Chemistry
2 answers:
MArishka [77]3 years ago
8 0

Answer:

1.008 has 4 significant figures (sig figs), and 3 decimals. See the steps with this sig fig calculator.

Explanation:

zalisa [80]3 years ago
3 0

Answer: The answer is 77.41 please let me know if I'm wrong :(

Explanation:

You might be interested in
Dinitrogen pentoxide is used in the preparation of explosives. If 7.93 mol of
Tpy6a [65]

The volume of O₂ produced: 84.6 L

<h3>Further explanation</h3>

Given

7.93 mol of  dinitrogen pentoxide

T = 48 + 273 = 321 K

P = 125 kPa = 1,23365 atm

Required

Volume of O₂

Solution

Decomposition reaction of dinitrogen pentoxide

2N₂O₅(g)→4NO₂(g)+O₂ (g)

From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :

= 0.5 x mol N₂O₅

= 0.5 x 7.93

= 3.965 moles

The volume of O₂ :

\tt V=\dfrac{nRT}{P}\\\\V=\dfrac{3.965\times 0.082\times 321}{1.23365}\\\\V=84.6~L

5 0
3 years ago
A hot metal plate at 150°C
Travka [436]
The air surrounding the hot plate would heat up through the process of convection
7 0
3 years ago
Protons are in the nucleus of the atom and have a positive charge.<br> True or False?
gladu [14]
True. They are positive charged! Hope this helps
3 0
3 years ago
What limitations are associated with the use of both<br> word and formula equations?
Dennis_Churaev [7]

Limitations of word equation and formula equation is that they do not express the quantities of reactant and product in the reaction.

Explanation:

Word equation expresses the chemical reaction in words. The reactants products and the direction of the reaction is mentioned in it. The information is used to write a chemical reaction. The word "reacted' shows the reactants and 'forms' show product. The sequence of reactions, moles of reactant and product is written.

Limitations:

Rate of reaction cannot be known.

Actual amount of product formed cannot be known.

eg: Addition of sodium oxide with water produces sodium hydroxide.

In formula equation symbols for element representation are used. The ratio of the elements in the reaction are also there. The atom numbers are indicated by the subscript number.

Limitations:

Concentration of both reactants and products is not mentioned.

The physical conditions of the reactants are not told

The thermodynamic conditions are not expressed as rate of reaction, pressure and temperature requirement.

Time taken to complete the reaction cannot be known.

Reaction mechanism cannot be observed by only chemical equations.

Value of actual yield is not given.

5 0
4 years ago
2C(s)+O2(g)2H2(g)+O2(g)H2O(l)→2CO(g)→2H2O(g)→H2O(g)ΔHΔHΔH=−222kJ=−484kJ=+44kJ Use the thermochemical data above to calculate the
sveticcg [70]

Answer : The change in enthalpy for the reaction is, 175 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The main reaction is:

H_2O(l)+C(s)\rightarrow CO(g)+H_2(g)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) 2C(s)+O_2(g)\rightarrow 2CO(g)     \Delta H_1=-222kJ

(2) 2H_2(g)+O_2(g)\rightarrow 2H_2O(g)    \Delta H_2=-484kJ

(3) H_2O(l)\rightarrow H_2O(g)    \Delta H_3=44kJ

Now we are dividing reaction 1 by 2, dividing reverse reaction 2 by 2 and then adding all the equations, we get :

(1) C(s)+\frac{1}{2}O_2(g)\rightarrow CO(g)     \Delta H_1=\frac{-222kJ}{2}=-111kJ

(2) H_2O(g)\rightarrow H_2(g)+\frac{1}{2}O_2(g)    \Delta H_2=\frac{484kJ}{2}=242kJ

(3) H_2O(l)\rightarrow H_2O(g)    \Delta H_3=44kJ

The expression for change in enthalpy of the given reaction is:

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(-111)+(242)+(44)

\Delta H=175kJ

Therefore, the change in enthalpy for the reaction is, 175 kJ

6 0
4 years ago
Other questions:
  • If the Density of an object is 5.2 g/cm 3 , and its volume is 3.7 cm 3 , what is its mass?
    11·2 answers
  • What is conductivity?
    6·2 answers
  • Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
    13·1 answer
  • When might a theory or scientific claim be modified or changed?
    13·1 answer
  • 2 Points<br> What was the purpose of the periodic table?
    11·1 answer
  • Please finish this <br> C3H8+5O2
    10·2 answers
  • Explain why heating a liquid causes it to evaporate more quickly.
    10·1 answer
  • Nitric acid (HNO3) reacts with ammonia (NH3) in aqueous solution. Use your knowledge of nitric acid to decide what type of react
    5·1 answer
  • Il See Periodic Table See Hint
    12·1 answer
  • Choose the atom or ion that is larger.<br><br> Select one:<br> a. S<br> b. S-2
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!