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kaheart [24]
4 years ago
11

If the Density of an object is 5.2 g/cm 3 , and its volume is 3.7 cm 3 , what is its mass?

Chemistry
2 answers:
Kay [80]4 years ago
8 0
19,24g
take density x volume
Lilit [14]4 years ago
5 0

Answer: mass = 19 grams

Explanation: Density is directly proportional to mass and indirectly proportional to the volume. So, the density formula is:

density=\frac{mass}{volume}

density and volume are given and the question asks to calculate the mass. So, the formula could be rearranged as:

mass = density x volume

Given density is \frac{5.2g}{cm^3} and the volume is 3.7cm^3 .

Let's plug in the values in the formula to calculate the mass:

mass = \frac{5.2g}{cm^3}*3.7cm^3

mass = 19.24 grams

Both the density and volume have two sig figs, so if the answer is round off to correct number of sig figs then the mass will be 19 grams.

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Answer:

Here's what I get  

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Thus, the removal of two electrons from Cu gives you Cu²⁺.

I found the ionization energies of Cu and used them to create those of Cu²⁺ (see table and graph below).

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8 0
3 years ago
What is the volume of 7.50 x 10^24 molecules of NH3 at STP?
Allushta [10]

27.9L

Explanation:

Given parameters:

Number of molecules = 7.5 x 10²⁴molecules

Condition = STP

Unknown:

Volume of gas = ?

Solution;

The volume of gas at STP is expressed below;

 Volume of gas = number of moles x 22.4

Number of moles = \frac{Number of molecules }{6.02 x 10^{23} }

    Now if we can obtain the value of the number of moles from the expression above, we can plug it back into the equation of the volume of gas at STP;

     Number of moles of NH₃ =  \frac{[tex]7.5 x 10^{24} }{6.02 x 10^{23} }[/tex]

   Number of moles of NH₃ = 12.5moles

Volume of gas = 12.5 x 22.4 = 27.9L

learn more:

Volume of gas at STP brainly.com/question/7795301

#learnwithBrainly

3 0
3 years ago
How many moles of Ag+ ions are present in 10 ml of a 0.75 M AgNO3 solution?
lana66690 [7]

Answer:

b. 7.5 x 10^-3

Explanation:

To solve this problem we need to keep in mind the <em>definition of molarity</em>:

  • Molarity = moles of solute / liters of solution

With the above information in mind it is possible to calculate the moles of solute, given the volume (10 mL) and concentration (0.75 M) of the solution:

  • First we<u> convert 10 mL to L</u> ⇒ 10 mL / 1000 = 0.01 L

Then we <u>calculate the moles of AgNO₃</u>:

  • moles of solute = Molarity * Liters of solution
  • 0.01 L * 0.75 M = 7.5x10⁻³ mol AgNO₃

<em>One mole of AgNO₃ contains one mole of Ag⁺</em>, thus the number of Ag⁺ moles is also 7.5x10⁻³.

5 0
3 years ago
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