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kaheart [24]
3 years ago
11

If the Density of an object is 5.2 g/cm 3 , and its volume is 3.7 cm 3 , what is its mass?

Chemistry
2 answers:
Kay [80]3 years ago
8 0
19,24g
take density x volume
Lilit [14]3 years ago
5 0

Answer: mass = 19 grams

Explanation: Density is directly proportional to mass and indirectly proportional to the volume. So, the density formula is:

density=\frac{mass}{volume}

density and volume are given and the question asks to calculate the mass. So, the formula could be rearranged as:

mass = density x volume

Given density is \frac{5.2g}{cm^3} and the volume is 3.7cm^3 .

Let's plug in the values in the formula to calculate the mass:

mass = \frac{5.2g}{cm^3}*3.7cm^3

mass = 19.24 grams

Both the density and volume have two sig figs, so if the answer is round off to correct number of sig figs then the mass will be 19 grams.

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Answer:

1.05 V

Explanation:

Since;

E°cell= E°cathode- E°anode

E°cathode= -0.40 V

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Equation of the process;

2Zr(s) + 4Cd^2+(aq) ---->2Zr^4+(aq) + 4Cd(s)

n= 8 electrons transferred

From Nernst's equation;

Ecell = E°cell - 0.0592/n log Q

Ecell= E°cell - 0.0592/8 log [0.5]/[0.5]

Since log 1=0

Ecell= E°cell= 1.05 V

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2 years ago
How do test with crash dummies, seat belts, and air bags illustrate newton's first law of motion??
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Provide a balanced molecular equation, total ionic, and net ionic equation for sodium phosphate and zinc acetate.
vivado [14]

Answer: Balanced molecular equation :

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

Total ionic equation:

6Na^+(aq)+3PO_4^{2-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)  

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2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)

Explanation:

Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as  product.

The balanced molecular equation will be,

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

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The net ionic equation will be,

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