Carbon Dioxide with water and sunlight produce glucose and oxygen
Answer:
Here's what I get
Explanation:
The ionization energy (I) is the energy required to remove an electron from an atom in the gaseous phase.
You can remove electrons in succession and measure the energies required as I₁, I₂, I₃, etc.
Thus, the removal of two electrons from Cu gives you Cu²⁺.
I found the ionization energies of Cu and used them to create those of Cu²⁺ (see table and graph below).
The electron configuration of Cu²⁺ is
Cu²⁺: 1s² 2s²2p⁶ 3s²3p⁶ 3d⁹
You can remove the nine 3d electrons and then there is a sudden jump from I₉ to I₁₀ as you break into the filled [Ar] configuration.
Similarly, there is big jump from I₁₇ to I₁₈ as you break into the filled [Ne] configuration.
27.9L
Explanation:
Given parameters:
Number of molecules = 7.5 x 10²⁴molecules
Condition = STP
Unknown:
Volume of gas = ?
Solution;
The volume of gas at STP is expressed below;
Volume of gas = number of moles x 22.4
Number of moles = 
Now if we can obtain the value of the number of moles from the expression above, we can plug it back into the equation of the volume of gas at STP;
Number of moles of NH₃ =
}{6.02 x 10^{23} }[/tex]
Number of moles of NH₃ = 12.5moles
Volume of gas = 12.5 x 22.4 = 27.9L
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Volume of gas at STP brainly.com/question/7795301
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Answer:
b. 7.5 x 10^-3
Explanation:
To solve this problem we need to keep in mind the <em>definition of molarity</em>:
- Molarity = moles of solute / liters of solution
With the above information in mind it is possible to calculate the moles of solute, given the volume (10 mL) and concentration (0.75 M) of the solution:
- First we<u> convert 10 mL to L</u> ⇒ 10 mL / 1000 = 0.01 L
Then we <u>calculate the moles of AgNO₃</u>:
- moles of solute = Molarity * Liters of solution
- 0.01 L * 0.75 M = 7.5x10⁻³ mol AgNO₃
<em>One mole of AgNO₃ contains one mole of Ag⁺</em>, thus the number of Ag⁺ moles is also 7.5x10⁻³.