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valentinak56 [21]
4 years ago
13

What limitations are associated with the use of both word and formula equations?

Chemistry
1 answer:
Dennis_Churaev [7]4 years ago
5 0

Limitations of word equation and formula equation is that they do not express the quantities of reactant and product in the reaction.

Explanation:

Word equation expresses the chemical reaction in words. The reactants products and the direction of the reaction is mentioned in it. The information is used to write a chemical reaction. The word "reacted' shows the reactants and 'forms' show product. The sequence of reactions, moles of reactant and product is written.

Limitations:

Rate of reaction cannot be known.

Actual amount of product formed cannot be known.

eg: Addition of sodium oxide with water produces sodium hydroxide.

In formula equation symbols for element representation are used. The ratio of the elements in the reaction are also there. The atom numbers are indicated by the subscript number.

Limitations:

Concentration of both reactants and products is not mentioned.

The physical conditions of the reactants are not told

The thermodynamic conditions are not expressed as rate of reaction, pressure and temperature requirement.

Time taken to complete the reaction cannot be known.

Reaction mechanism cannot be observed by only chemical equations.

Value of actual yield is not given.

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When 1.550 g of liquid hexane (C6H14) undergoes combustion in a bomb calorimeter, the temperature rises from 25.87∘C to 38.13∘C.
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Explanation:

1). The given data is as follows.

       T_{i} = 25.87^{o}C,      T_{f} = 38.13^{o}C

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Therefore, enthalpy of reaction in kJ/mol hexane is as follows.

            \Delta E_{rxn} = \frac{-70.25 KJ}{0.018 mol}

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Thus, we can conclude that \Delta E_{rxn} for the reaction in kJ/mol hexane is -3.90 \times 10^{3} kJ/mol .

2).  As we know that,

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                                  = \frac{1.55}{(7 \times 12 + 8 \times 1)}

                                   = 0.017 mol

       \Delta E_{rxn} = \E_{rxn} per mol \times \text{number of moles}

                      = -3.91 \times 10^{3} \times 0.017

                      = -65.875 kJ

As,    \Delta E_{rxn} = C \times \Delta T&#10;

                    -65.875 kJ = -C \times (37.57 - 23.12)^{o}C

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Hence, heat capacity of the bomb calorimeter is 4.56 kJ/^{o}C.

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