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3 years ago

What is conductivity?

Chemistry

2 answers:

DiKsa [7]3 years ago

6 0

Conductivity is a metal conduct heat and electricity well.

Delocalized electrons = easy electron movement.
Moving electrons carry current, thermal energy.
More valence electrons, larger atomic radius = higher conductivity.

Metals are malleable, ductile, and exhibit luster.

Delocalized electrons = easy to deform metal.
Easy electron movement = "flexible" bonds.
Metals = malleable and ductile instead of brittle.
Movement of electrons between bands = shiny, metallic luster.
Oscillation of electrons between bands emits light.

Hope this helps!

r-ruslan [8.4K]3 years ago

5 0

The degree to which a specified material conducts electricity, calculated as the ratio of the card density in the material to the electric field that causes the flow of current. It is the reciprocal of the resistivity.

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What else can copper react with?

FinnZ [79.3K]

Answer:

copper

Explanation:

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3 years ago

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Explain how a substances flammability can indicate a chemical change.

Marat540 [252]

Answer:

This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

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3 years ago

A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is

Charra [1.4K]

Answer:

$[H^{+}] = 0.761 \frac{mol}{L}$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

$pH = 0.119$

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

$n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L) \\ n_{H^{+} } from HNO_{3} = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)$

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

$n_{H^{+} } from HCl = (5.00)(0.093)$

$n_{H^{+} } from HCl = 0.465 mol$

$n_{H^{+} } from HNO_{3} = (8.00)(0.037)$

$n_{H^{+} } from HNO_{3} = 0.296 mol$

$n_{H^{+}(total) } = 0.296 + 0.465$

$n_{H^{+}(total) } = 0.761 mol$

For molar concentration of hydrogen ions:

$[H^{+}] = \frac{n_{H^{+}}(mol)}{V(L)}$

$[H^{+}] = \frac{0.761}{1.00}$

$[H^{+}] = 0.761 \frac{mol}{L}$

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

$K_{w} = [H^{+} ][OH^{-} ]$

$[OH^{-}]=\frac{Kw}{[H^{+}] }$

$[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

The pH of the solution can be measured by the following formula:

$pH = -log[H^{+} ]$

$pH = -log(0.761)$

$pH = 0.119$

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3 years ago

Soluble ionic compounds that dissociate naerly completely when dissolved are classified as _______.

Anettt [7]

The answer is D. Strong electrolytes

Strong electrolyte is a solute or solution that completely or almost completely dissociates when in solution. These are good conductors of electricity only when in molten/aqueous solution.

Strong electrolyte(aq) → Cation+(aq) + Anion−(aq)

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3 years ago

Which statement is true about the relationship between entropy and spontaneity? O Spontaneous reactions tend to lead to higher e

dimulka [17.4K]

Answer:

The true statement is: Spontaneous reactions tend to lead to higher entropy.

Explanation:

The spontaneity of a reaction is linked to the value of Gibbs free energy (ΔG°). The more negative is this value, the more spontaneous is a reaction. At the same time, Gibbs free energy depends on enthalpy (ΔH°) and entropy (ΔS°), according to the following expression:

ΔG° = ΔH° - T.ΔS°

We can see that higher entropies (higher ΔS°) lead to more negative ΔG°, thus, more spontaneous reactions.

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3 years ago