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Mariana [72]
3 years ago
6

What is conductivity?

Chemistry
2 answers:
DiKsa [7]3 years ago
6 0

Conductivity is a metal conduct heat and electricity well.

  • Delocalized electrons = easy electron movement.
  • Moving electrons carry current, thermal energy.
  • More valence electrons, larger atomic radius = higher conductivity.

Metals are malleable, ductile, and exhibit luster.

  • Delocalized electrons = easy to deform metal.
  • Easy electron movement = "flexible" bonds.
  • Metals = malleable and ductile instead of brittle.
  • Movement of electrons between bands = shiny, metallic luster.
  • Oscillation of electrons between bands emits light.

Hope this helps!

r-ruslan [8.4K]3 years ago
5 0
The degree to which a specified material conducts electricity, calculated as the ratio of the card density in the material to the electric field that causes the flow of current. It is the reciprocal of the resistivity.
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Rank these compounds by highest boiling point to lowest boiling point? Pentane, neopentane, isopentane
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<span>Pentane has a boiling point of 36.1 C, while isopentane boils at 27.7C. Neopentane has the lowest boiling point at 9.5 C. Therefore from highest to lowest boiling points, it is pentane, isopentane, and neopentane.</span>
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3 years ago
What is the scientific term for rocks made in lava?
Elden [556K]

The answer is d. extrusive.


The other term for it is <em>igneous rock</em>. Igneous rock is made in lava, and another term for igneous rock is extrusive rock.


have a great day! Brainliest is greatly appreciated, and please let me know if you need help with anything else ;)

5 0
3 years ago
Read 2 more answers
Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
3 years ago
Is density a chemical or physical property of a substance?
pychu [463]

Answer:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

I hope this helps you understand! <3

8 0
3 years ago
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