Answer:
Equilibrium Constant = (3.60 × 10⁶²)
Explanation:
The change in Gibb's free energy for a galvanic cell is given as
Δ = -nFE°
where n = number of electrons transferred = 5 for this reaction
F = Faraday's constant = 96500 C
E° = cell potential = +0.74 V
But the change in Gibb's free energy for galvanic cell reaction is also given as
ΔG = -RT In K
R = molar gas constant = 8.314 J/mol.K
T = absolute temperature in Kelvin = 25 + 273.15 = 298.15 K
K = Equilibrium constant.
Equating these two expressions
-nFE° = - RT In K
RT In K = nFE°
In K = (nFE°) ÷ (RT)
In K = (5 × 96500 × 0.74) ÷ (8.314 × 298.15)
In K = 144.04
K = e^(144.04)
K = (3.60 × 10⁶²)
Hope this Helps!!!
