Answer:
Explanation:
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In this case, according to the given information it will be firstly necessary to set up the chemical equation taking place:
We infer we need to calculate the moles of NH3 by using both of the moles of N2 and H2 at the beginning, in order to identify the limiting reactant:
Thus, since hydrogen yields the fewest moles of ammonia, we conclude that we are just able to yield 4 moles of NH3.
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In a chemical reaction one or more reactants combine or react to form one or more product(s) with different chemical and physical properties.
When aqueous sodium sulfide reacts with aqueous copper(II) nitrate results in the formation of aqueous sodium nitrate and solid copper(ll) sulfide.
First, identify the chemical symbols for the elements in the compounds.
Sodium sulphide =
Copper(II) nitrate =
Sodium nitrate =
Copper(II) sulfide =
The chemical reaction is given as:
Now, balance the chemical equation:
For balance the equation, multiply by 2.
Thus,
Answer:
The explanations are given in the section below
Explanation:
First step:
We need to understand the acid-base equilibrium of the reaction. Bear in mind that the conjugate acid-base pairs are species that differ by one proton. Furthermore, one is a Lewis acid (meaning the ability to protons) and the conjugate base (accepts protons)
A simple conjugate base is obtained by removing one proton from an acid as shown below:
HX ⇄ A⁻ + H⁺
The diagrams are as follows:
