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Kobotan [32]
3 years ago
12

1) Which equation graphs as a line? A) y = 2x3 B) y = x2 + 3 C) y = 1 2 x D) y = 1 2 x2

Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

B) y=2x+3

Step-by-step explanation:

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5(-2)^3 5(-2) is -10 to the power of 3 is -1000
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What is 20% of 100 in whole money
Kryger [21]
%=percent
percent means parts out of 100
20%=20/100
'of' means multiply

20% of 100  units means
20/100 times 100 units=2000/100 units=20 units
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Mario has 3.875 liters of juice at the beginning of the day he drinks 2.79 liters during the day how much juice is left over st
katen-ka-za [31]

Answer:

The juice left at the end of the day is 1.085 liters.

Step-by-step explanation:

Juice at the beginning of the day: 3.875 liters

Juice drink by Mario during the day: 2.79 liters

Juice left at the end of the day = Juice at the beginning of the day - Juice drink by Mario during the day

                                                  = 3.875 - 2.79

                                                  = 1.085 liters

7 0
3 years ago
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E<br> 6x<br> 1.) 12x^4 y^8z^7/ 4xy^3z^2
BartSMP [9]

Answer:

Maya used a drawing to divide 86. She made groups of 17 with 1 left over. Draw a picture to determine how many groups Maya made.

Step-by-step explanation:

It might be the wrong answer! Sorry

7 0
2 years ago
The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate
soldi70 [24.7K]

Answer:

a) V = 33510.322\,in^{3}, b) A_{s} = 5026.548\,in^{2}, c) \% V = 0.450\,\%, \%A_{s} = 0.300\,\%.

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

V = \frac{4}{3}\pi \cdot r^{3}

A_{s} = 4\pi \cdot r^{2}

a) The volume of the sphere is:

V = \frac{4}{3}\pi \cdot (20\,in)^{3}

V = 33510.322\,in^{3}

b) The surface area of the sphere is:

A_{s} = 4\pi \cdot (20\,in)^{2}

A_{s} = 5026.548\,in^{2}

c) The total differentials for volume and surface area of the sphere are, respectively:

\Delta V = 4\pi\cdot r^{2}\,\Delta r

\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)

\Delta V = 150.796\,in^{3}

\Delta A_{s} = 8\pi\cdot r \,\Delta r

\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)

\Delta A_{s} = 15.080\,in^{2}

Relative errors are presented hereafter:

\%V = \frac{\Delta V}{V}\times 100\%

\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%

\% V = 0.450\,\%

\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%

\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%

\%A_{s} = 0.300\,\%

4 0
3 years ago
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