Yes it is because none of the x are the same number making it a function.
Answer:
Ur answer is #1 = A number line from negative 10 to 10 is shown with numbers labeled at intervals of 2. An arrow is shown from point 0 to negative 2. Another arrow points from negative 2 to 8.
Step-by-step explanation:
The arrow from 0 to -2 represents the initial "-2" of the problem. <em>Adding </em>-10 would put an arrow of length 10 from that point to the left to -12. However, you are <em>subtracting </em>-10, so that arrow is reversed and goes from -2 to +8.
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➷ Housing: 1800/4500 x 100 = 40%
Transportation: 800/4500 x 100 = 17.7%
Utilities: 175/4500 x 100 = 3.8%
Food: 550/4500 x 100 = 12.2%
Savings: 300/4500 x 100 = 6.6%
Loan: 300/4500 x 100 = 6.6%
Other: 575/4500 X 100 = 12.7%
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Answer:
Volume of the cone = 
Step-by-step explanation:
Height of the cone = 
Radius of the cone = 
Volume of a cone is:

As, 
Volume is:

The volume of the cone is: 
Given a complex number in the form:
![z= \rho [\cos \theta + i \sin \theta]](https://tex.z-dn.net/?f=z%3D%20%5Crho%20%5B%5Ccos%20%5Ctheta%20%2B%20i%20%5Csin%20%5Ctheta%5D)
The nth-power of this number,

, can be calculated as follows:
- the modulus of

is equal to the nth-power of the modulus of z, while the angle of

is equal to n multiplied the angle of z, so:
![z^n = \rho^n [\cos n\theta + i \sin n\theta ]](https://tex.z-dn.net/?f=z%5En%20%3D%20%5Crho%5En%20%5B%5Ccos%20n%5Ctheta%20%2B%20i%20%5Csin%20n%5Ctheta%20%5D)
In our case, n=3, so

is equal to
![z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20%5Crho%5E3%20%5B%5Ccos%203%20%5Ctheta%20%2B%20i%20%5Csin%203%20%5Ctheta%20%5D%20%3D%20%285%5E3%29%20%5B%5Ccos%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%2B%20i%20%5Csin%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%5D)
(1)
And since

and both sine and cosine are periodic in

, (1) becomes