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3 years ago

For 32 hours of work, you are paid $244.80. How much would you receive for 37 hours?

Mathematics

1 answer:

Serga [27]3 years ago

7 0

Answer:

$283.05

Step-by-step explanation:

first divide $244.80 by 32, to find out how much you are making hourly. in this case you are making $7.65 an hour

next, multiply $7.65 by 5, to add the 5 hours, in this case you get $38.25.

next, add $38.25 to $244.80 and you get your answer!

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Help me please help

solniwko [45]

Answer:

I think its c I'm not sure

4 0

2 years ago

Which choice is equivalent to the expression below?

alekssr [168]

Answer: OPTION A

Step-by-step explanation:

We need to remember that Product of powers property, which states that:

$(a^m)(a^n)=a^{(m+n)}$

Let's check the options:

A. For $5^9*5^{\frac{9}{10}}*5^{\frac{6}{100}}*5^{\frac{9}{1000}}$ you can apply the property mentioned before. Then:

$5^{(9+\frac{9}{10}+\frac{6}{100}+\frac{9}{1000})=5^{9.969}$

(It is the equivalent expression)

B. Add the exponents:

$5^9*5^{(\frac{9}{10}+\frac{9}{10}+\frac{6}{1000})=5^{10.806}$

(It is not the equivalent expression)

C. For $5^9*5^{\frac{96}{10}}*5^{\frac{9}{100}}}$ you can apply the property mentioned before. Then:

$5^{(9+\frac{96}{10}+\frac{9}{100})=5^{18.69}$

(It is not the equivalent expression)

D. We know that $5^{9.969}=9,290,347.808$ and we maje the addition indicated in this option, we get:

$5^9+5^{\frac{9}{10}}+6^{\frac{6}{100}}=1,953,130.37$

(It is not the equivalent expression)

6 0

3 years ago

Read 2 more answers

Ill give u brainly if u help on this one too please !

mrs_skeptik [129]

Answer:

The correct answer is B!

Step-by-step explanation:

I hope it helps you Sir (or ma'am.)

8 0

2 years ago

Salomon tracks the weight of his new puppy every 2 weeks. She weighs 10 lbs the

Gekata [30.6K]

Equation (B) "y = 3x + 10" represents the growth of the puppy.

<h3>What are equations?</h3>

An equation is a mathematical formula where the "equal to" sign appears between two expressions having the same value.
Like 3x plus 5 equals 15, for example.
Different types of equations exist, such as linear, quadratic, cubic, and others.
The three primary forms of linear equations are the slope-intercept form, standard form, and point-slope form.

So, the equation that represents the situation:

The weight increase is: (10, 13, 16, 19, 22, 25)
We can observe that every time, there is a rise of 3lbs of weight.
Now, let 10 be a constant as the weight is starting from 10 lbs.
And 'x' be the number of time Salomon tracks the weight.

Then:

y = 3x + 10

For example, Salomon checks the weight for the 6th time then:

y = 3x + 10
y = 3(5) + 10
y = 15 + 10
y = 25

So, the equation is correct.

Therefore, equation (B) "y = 3x + 10" represents the growth of the puppy.

Know more about equations here:

brainly.com/question/28937794

#SPJ13

The correct question is given below:
Salomon tracks the weight of his new puppy every 2 weeks. She weighs 10 lbs the day he brings her home. His list for her first 6 "weighs" is as follows: (10, 13, 16, 19, 22, 25}

Which equation represents the growth of the puppy? Select one:

A. y = x + 3

B. y = 3x + 10

C. y = 10x + 3

D. y = x + 10

8 0

6 months ago

1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,

crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

$PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}$

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

$PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111$

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

$PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666$

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

$PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222$

3 0

3 years ago