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3 years ago

Help finding the length of arc RS using 3.14 for pi

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

the answer is 17

Step-by-step explanation:

katen-ka-za [31]3 years ago

5 0

Answer:

$8.48in$

Step-by-step explanation:

The length of arc RS is given by:

$l=\frac{\theta}{360}\times 2\pi r$

From the diagram the radius is $r=6.48 in$ and the central angle of sector RS is $\theta=150\degree$

We use $\pi=3.14$ and substitute the radius and central angle to obtain:

$l=\frac{150}{360}\times 2\times3.14\times 6.48in$

We simplify to get:

$l=\frac{5}{12}\times 2\times 6.48in$

$l=\frac{5}{6}\times 3.14\times 6.48in^2$

$l=8.48in$

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Write 0.00467 in standard form

meriva

Answer:

$\frac{0.00467}{100000}$

Step-by-step explanation:

Given :

0.00467

Now,

$0.00467=\frac{0.00467}{100000}$

Standard form of given equation is :

$\frac{0.00467}{100000}$

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3 years ago

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3 years ago

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What is the difference between discrete vs continuous data

Sergeeva-Olga [200]

With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)

On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4).

-------------------------------------

With that in mind, we have the following answers

1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint

2) Continuous data. Like time values, temperatures can be averaged as well.

3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.

4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds.

5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.

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3 years ago

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

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3 years ago

Draw two different shapes with a perimeter of 16 units. What is the area of each shape?

Nadusha1986 [10]

Shape #1: A square.
Every side is 4 units long.
The perimeter is 16 units.
The area is 16 square units.

Shape #2: A rectangle.
The length is 7.9 units.
The width is 0.1 unit.
The perimeter is 16 units.
The area is 0.79 of a square unit.

Shape #3: A circle.
The diameter is (16/π) units. (about 5.093 units)
The perimeter (circumference) is 16 units.
The area is (64/π) square units. (about 20.37 square units)

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3 years ago

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