Idk honestly, haven’t cryied since I ate a warhead
We have a three unknown, 4 equation homogeneous system. These always have at least (0,0,0) as a solution. Let's write the equations, one column at a time.
1a + 0b + 0c = 0
-1a + 1b +0c = 0
0a - 1b + c = 0
0a + 0b + -1 c = 0
We could do row reduction but these are easy enough not to bother.
Equation 1 says
a = 0
Equation 4 says
c = 0
Substituting in the two remaining,
-1(0) + 1b + 0c = 0
b = 0
0(0) - 1b + 0 = 0
b = 0
The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)
Answer:
output is -17
Step-by-step explanation:
x is input, y is output. You do y = -24 + 7
then y = -17
Yeah, x= 7/2 and y= -5/2
Please mark as brainliest and I hope this helps
9 miles, you dont even need much math, just common sense. divide 12 by 4 and you get three. multiply 3 by 3 to get 9.
