Given:
The graph of function g(x) is a transformation of the graph of function f(x) = x²
As shown: the graph of g(x) is open down
So, we will reflect f(x) over the x-axis, the function will be ⇒ -x²
And there is horizontal compression so, the factor of compression will be > 1
So, the function will be ⇒ -2x²
Finally, there is a vertical shift down 3 units
So,
Answer:
Distribute
8
−
4
=
2
(
4
−
4
)
8x-4={\color{#c92786}{2(4x-4)}}
8x−4=2(4x−4)
8
−
4
=
8
−
8
8x-4={\color{#c92786}{8x-8}}
8x−4=8x−8
2
Add
4
4
4
to both sides of the equation
8
−
4
=
8
−
8
8x-4=8x-8
8x−4=8x−8
8
−
4
+
4
=
8
−
8
+
4
8x-4+{\color{#c92786}{4}}=8x-8+{\color{#c92786}{4}}
8x−4+4=8x−8+4
3
Simplify
Add the numbers
Add the numbers
8
=
8
−
4
8x=8x-4
8x=8x−4
2 more steps
Result
0
=
−
4
0=-4
0=−4
The input is a contradiction: it has no solutions
This could be wrong because I'm going into the fifth grade but wouldn't it just be (7,-3)?
Hello :
all n in N ; n(n+1)(n+2) = 3a a in N or : <span>≡ 0 (mod 3)
1 ) n </span><span>≡ 0 ( mod 3)...(1)
n+1 </span>≡ 1 ( mod 3)...(2)
n+2 ≡ 2 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 0×1×2 ( mod 3) : ≡ 0 (mod 3)
2) n ≡ 1 ( mod 3)...(1)
n+1 ≡ 2 ( mod 3)...(2)
n+2 ≡ 3 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 1×2 × 3 ( mod 3) : ≡ 0 (mod 3) , 6≡ 0 (mod)
3) n ≡ 2 ( mod 3)...(1)
n+1 ≡ 3 ( mod 3)...(2)
n+2 ≡ 4 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 2×3 × 4 ( mod 3) : ≡ 0 (mod 3) , 24≡ 0 (mod3)
Answer:
Step-by-step explanation:
Multiply 0.60 with 43
Multiply 0.95 with 25
You will get $49.55 which is below $50
