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Montano1993 [528]
4 years ago
15

A unit of heat energy that was formerly used frequently was the calorie. Look up the definition of the calorie in your textbook

or a handbook and record it here. Calculate the calorimeter constant for your calorimeter in cal/°C .
Chemistry
1 answer:
dybincka [34]4 years ago
8 0

Answer and Explanation:

Calorie is the unit of heat energy . There are 2 units with the same name 'calorie' which is widely used.

'The amount of heat energy required to increase the temperature of 1 gram of water by mass by 1^{\circ}C or 1 K is known as small calorie or gram calorie'.

Another one is large calorie which can be defined as :

'The amount of heat energy required to make arise in temperature of water 1 kg by mass by 1^{\circ}C or 1 K is known as large calorie or  kilcalorie and is represented as Cal or kcal'.

After the adoption of SI system, thee units of the metric system cal, C or kilocal are considered deprecated or obsolete with the SI unit for heat energy as 'joule or J'

1 cal = 4.184 J

1C or 1 kilocal = 4184 J

Calorimeter constant:

Calorimeter constant, represented as 'C_{cal}' is used to quantify the heat capacity or the amount of heat of a calorimeter.

It can be calculated by ther given formula:

{\displaystyle C_{cal}}={\frac {\Delta {H}}{\Delta {T}}}}}

where,

{\Delta {T}} = corresponding temperature change

{\Delta {H} = enthalpy change

Its unit is J/K or J/1^{\circ}C[/tex] which can be convertyed to cal/1^{\circ}C[/tex] by dividing the calorimeter constant by 4.184 or 4184 accordingly.

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Describe what happens to the particles in a chocolate bar as it melts.
Margarita [4]

Answer:

The correct answer is d. As the chocolate bar changes from a solid to a liquid the particles move around more.

Explanation:

When a chocolate bar melts, it suffers a <u>physical</u> change: a change of state from solid to liquid. In the liquid state, the particles move around more, because they have more kinetic energy (more velocity) and more freedom to move than in solid state. Thus, as the solid became into a liquid, the particles move more.

5 0
4 years ago
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A generator is not required to generate electrical energy when which of the following energy sources is used?
Anon25 [30]

Answer:

think it's C but my gut is telling me A

Explanation:

5 0
3 years ago
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3 moles of anything is how many particles?
Natali [406]

Answer:

<h2>1.806 × 10²⁴ particles</h2>

Explanation:

The number of particles in a substance can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

<h3>1.806 × 10²⁴ particles</h3>

Hope this helps you

3 0
3 years ago
What heavier element is created when hydrogen atoms fuse together in the sun’s core?
sergey [27]

Answer:

Helium is created from hydrogen in the sun's core.

Four hydrogen-1 nuclei fuse to produce

  • one helium-4 nucleus, two neutrons,
  • two positrons, and
  • two electron neutrinos.

Explanation:

Step One:

{\rm ^1_1 H + ^1_1 H\to ^2_1 H + e^{+}} + v_e.

Two hydrogen-1 nuclei fuse. One proton will convert to a neutron. The products will be

  • one hydrogen-2 nucleus,
  • one positron, and
  • one electron neutrino.

Step Two:

\rm ^1_1 H +^2_1 H \to ^3_2 He.

There are plenty of hydrogen-1 nuclei available in the core of the sun. The hydrogen-2 nucleus from step one will fuse with a hydrogen-1 nucleus. The product is

  • one helium-3 nucleus.

Step Three

\rm ^3_2 He + ^3_2 He \to ^4_2 He + ^1_1 H + ^1_1 H.

Two helium-3 nuclei from step two react with each other. The products are:

  • one helium-4 nucleus, and
  • two hydrogen-1 nuclei.

The overall reaction will be:

{\rm 6\; ^1_1 H \to ^4_2 He + 2\; ^1_1 H+2\; e^{+}}+v_\text{e}.

{\rm 4\; ^1_1 H \to ^4_2 He + 2\; e^{+}} + v_\text{e}

In other words, hydrogen nuclei in the core of the sun fuse together to form helium.

6 0
3 years ago
How many molecules of Iron(II)oxide are present in 35.2*10^-23 g of Iron (II)oxide?
slava [35]

Answer:

R.F.M of Iron (II) oxide :

{ \tt{ = (56 \times 2) + (16 \times 3)}} \\  = 160 \: g

Moles :

{ \tt{ \frac{35.2 \times  {10}^{ - 23} }{160} }} \\  = 2.2 \times  {10}^{ - 24}  \: moles

Molecules :

{ \tt{ = 2.2 \times  {10}^{ - 24}  \times 6.02 \times  {10}^{23} }} \\  = 1.3244 \: molecules

4 0
3 years ago
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