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Montano1993 [528]
3 years ago
15

A unit of heat energy that was formerly used frequently was the calorie. Look up the definition of the calorie in your textbook

or a handbook and record it here. Calculate the calorimeter constant for your calorimeter in cal/°C .
Chemistry
1 answer:
dybincka [34]3 years ago
8 0

Answer and Explanation:

Calorie is the unit of heat energy . There are 2 units with the same name 'calorie' which is widely used.

'The amount of heat energy required to increase the temperature of 1 gram of water by mass by 1^{\circ}C or 1 K is known as small calorie or gram calorie'.

Another one is large calorie which can be defined as :

'The amount of heat energy required to make arise in temperature of water 1 kg by mass by 1^{\circ}C or 1 K is known as large calorie or  kilcalorie and is represented as Cal or kcal'.

After the adoption of SI system, thee units of the metric system cal, C or kilocal are considered deprecated or obsolete with the SI unit for heat energy as 'joule or J'

1 cal = 4.184 J

1C or 1 kilocal = 4184 J

Calorimeter constant:

Calorimeter constant, represented as 'C_{cal}' is used to quantify the heat capacity or the amount of heat of a calorimeter.

It can be calculated by ther given formula:

{\displaystyle C_{cal}}={\frac {\Delta {H}}{\Delta {T}}}}}

where,

{\Delta {T}} = corresponding temperature change

{\Delta {H} = enthalpy change

Its unit is J/K or J/1^{\circ}C[/tex] which can be convertyed to cal/1^{\circ}C[/tex] by dividing the calorimeter constant by 4.184 or 4184 accordingly.

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The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
krok68 [10]

Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = 2.83\times 10^{-3}

a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=3.96\times 10^{-3}min^{-1}

The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

6 0
3 years ago
What is the atomic number of the element located in group 16
laila [671]

Answer:

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Explanation:

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7 0
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A 75.0-milliliter lightbulb is filled with neon. There are 7.16 × 10-4 moles of gas in it, and the absolute pressure is 116.8 ki
Fantom [35]

Answer:- 1467 K

Solution:- It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.

Given: n=7.16*10^-^4moles

V = 75.0 mL = 0.0750 L

P = 116.8 kPa

We know that, 101.325 kPa = 1 atm

So, 116.8kPa(\frac{1aym}{101.325kPa})

= 1.15 atm

R is universal gas constant and it's value is 0.0821\frac{atm.L}{mol.K} .

T = ?

Let's plug in the values in the equation and solve it for T.

1.15(0.0750)=7.16*10^-^4*0.0821(T)

0.08625 = 0.00005878(T)

T=\frac{0.08625}{0.00005878}

T = 1467 K

So, the temperature of the light bulb would be 1467 K.

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