The correct Answer based on my calculations is C
Answer:
Sulfur has the same amount, like all the other elements in group 16, has six valence electrons.
Explanation:
Answer:
The balanced half-reaction in which sulfate ion is reduced to sulfite ion is a two electron process
Explanation:
In the sulfate anion, S, acts with +6 in the oxidation number
SO₄⁻²
This is the anion from the sulfuric acid, when it lost the 2 protons
H₂SO₄ → 2H⁺ + SO₄⁻²
In the sulfite anion, S, acts with +4 in the oxidation number.
SO₃⁻²
This is the anion, generated when the sulfurose acid lost the 2 protons.
H₂SO₃ → SO₃⁻² + 2H⁺
In acidic medium
2H⁺ + SO₄⁻² + 2e⁻ → SO₃⁻² + H₂O
In basic medium
H₂O + SO₄⁻² + 2e⁻ → SO₃⁻² + 2OH⁻
Answer:
C
Explanation:
The molecule has 8 carbon atoms joined by 7 C-C bonds.
The first two diagrams show 6 carbon atoms, not 8.
The last two diagrams show line segments representing C-C bonds. Only choice C shows 7 such segments.
The appropriate choice is C.
