Ask question

Ask question

All categories

2 years ago

11

What is the charge of that particle? A). +e B).-2/3 e C).0 D).+2/3

1 answer:

Fynjy0 [20]2 years ago

5 0

A). +e according to quantisation of charge

You might be interested in

Idk how to do this at all!!!

sergey [27]

Hello there!

I am not really sure which part you are talking about but let me answer some of them.

First, you need to read the information they gave you about glucose etc..

13- What is produced in photosynthesis?
"Photosynthesis is essential for all life on earth, because it provides food and oxygen."

Thus, the answer is: Photosynthesis produced food and oxygen.

14- What is the glucose used for?
"The glucose produced is used by the plant for energy and growth."

Thus, the answer is: The glucose used for energy and growth of the plants.

15- What is the oxygen used for?
"The oxygen produced is released into the air for us to breath."

Thus, the answer is: The oxygen used for us to breath.

I hope this helps!

Let me know if you have questions about the answer.

3 0

3 years ago

Somebody help me asap please giving brainliest

Serggg [28]

Answer:

fire > rocks > air

3 0

3 years ago

Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr

VikaD [51]

Answer : The value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

Explanation :

The balanced cell reaction will be,

$Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)$

The half-cell reactions are:

Oxidation reaction (anode) : $Pb(s)\rightarrow Pb^{2+}(aq)+2e^-$

Reduction reaction (cathode) : $2Ag^+(aq)+2e^-\rightarrow 2Ag(g)$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

$\Delta G^o=-2\times 96500\times 0.93$

$\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol$

Now we have to calculate the value of 'K'.

$\Delta G^o=-RT\ln K$

where,

$\Delta G_^o$ = standard Gibbs free energy = -180 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

$-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K$

$K=3.6\times 10^{31}$

Therefore, the value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

5 0

3 years ago

If an isotope has an atomic number of 8 and a mass number of 18 how many neutrons

Artemon [7]

It will be Oxygen . And total 8 protons, 8 electrons and 9 neutrons are present in it.

6 0

3 years ago

Predict whether each of the following oxides is ionic or molecular: SnO2, Al2O3, CO2, Li2O, Fe2O3, H2O

KatRina [158]

Answer:

Explanation:

Ionic compounds are formed by combining a metal and a nonmetal.

Molecular compounds are formed by two or more nonmetals.

3 0

3 years ago

Read 2 more answers