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olya-2409 [2.1K]
3 years ago
10

If one ball with a momentum of 50 kg·m/s hits a ball at rest and no other forces are acting on either ball, what's the total mom

entum of both balls after the collision?
A. 0 kg·m/s
B. 25 kg·m/s
C. 100 kg·m/s
D. 50 kg·m/s
Chemistry
1 answer:
vitfil [10]3 years ago
5 0

Answer:

The answer is (D) 50 kg·m/s   (PF Test)

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2. Calculate the pressure in Pa of a brick, which weighs 40 lbs (178N) sitting flat on the
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Answer:

P =  741.7 Pa

Explanation:

Pressure:

It is the force applied on object per unit area. The force is applied perpendicular to the surface.

Mathematical expression:

P = F/A

P = pressure

F = force

A = area

Given data:

Weight = 178 N

Area = 10 cm × 24 cm

Pressure = ?

Solution:

Area = 10 cm × 24 cm

Area = 240 cm²

Area = 240 /10000 = 0.024 m²

Formula:

P = F/A

P = 178 N / 0.024 m²

P = 741.7 Nm⁻²

Nm⁻² = Pa

P =  741.7 Pa

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3 years ago
When do we classify a disease as epidemic
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Explanation:

An epidemic (from Greek ἐπί epi "upon or above" and δῆμος demos "people") is the rapid spread of disease to a large number of people in a given population within a short period of time.

3 0
3 years ago
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1s22s22p63s23p64s13d10 which element is this
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Answer:

Copper

Explanation:

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3 years ago
Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

3 0
3 years ago
Two very stable compounds, Freon-12 and Freon-14, are used as liquid refrigerants. A Freon-12 molecule consists of one carbon at
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81. There is 1 carbon, 2 chlorine and fluorine atoms in Freon 12. To draw them it forms a cross with C in the middle and Cl and F both on the opposite side. 
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      l
F - C- F
      l
     Cl

82. Freon-12 and Freon-14 are called halocarbons or just halides. 


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3 years ago
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