<u>Complete Question:</u>
Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.
<u>Correct Answer:</u>
A) 
B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
<u>Step-by-step explanation:</u>
a. Write an equation to represent the area of the reduced image.
Let the reduced dimensions is by x , So the new dimensions are

According to question , Area of new image is :
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So the equation will be :
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b. Find the dimensions of the reduced image
Let's solve : 
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By Quadratic formula :
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x = 15 is rejected ! as 15 > 10 ! Side can't be negative
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Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
The 4 in 42,672 is 40,000
And the 4 in 37,426 is 400
The answer is 100
Answer:
The answer is 2(the square root of 65 )
Step-by-step explanation:
Plug ( -6, 2) and (8, 10) into the distance formula and solve.
Distance = the square root of ((x2 - x1)^2 + (y2 - y1)^2))
Distance = the square root of ((8 - -6)^2 + (10 - 2)^2))
Distance = the square root of (14^2 + 8^2)
Distance = the square root of (196 + 64)
Distance = the square root of 260 which can be simplified to 2(the square root of 64)
Answer:
Multiply the radius (r), by 2 then divide the angle measure, x, by 4.
Step-by-step explanation: