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laila [671]
3 years ago
12

Can somebody please help with these

Physics
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

Fusion

Fission

Explanation:

The first problem describes a nuclear fusion process. In this process;

  • small atomic nuclei combines to form a larger one.
  • it is accompanied by a large release of energy
  • this energy provides the needed temperature to set up another light nuclei to fuse.

The second problem describes nuclear fission,

  • a heavy nuclide is bombarded with a neutron.
  • the product formed becomes unstable and subsequently breaks down.
  • This leads to a series of chain reactions until stability is attained.
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Use the drop-down menu to answer the question. In the equation I = v over r , what does I stand for? please help
ExtremeBDS [4]

Answer:

Current

Explanation:

The equation you mentioned is also known as Ohm's law, which can be applied for any circuit containing a battery and one (or more) resistors:

V=IR

where

V is the voltage

I is the current

R is the resistance

We can re-arrange the equation and rewrite it explicitely for I, the current, to match the equation mentioned in the text of the question, and we have:

I=\frac{V}{R}

6 0
3 years ago
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If three forces F1 = 20N, 300NE, F2 = 50N along W, F3 = 40N 500NW act on a body. Find the resultant in magnitude and direction.​
patriot [66]

Answer:

110N north west

Explanation:

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4 0
3 years ago
An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and
Kobotan [32]

Answer:

Explanation:

Given that

The electric fields of strengths E = 187,500 V/m and

and The magnetic  fields of strengths B = 0.1250 T

The diameter d is 25.05 cm which is converted to 0.2505m

The radius is (d/2)

= 0.2505m / 2 = 0.12525m

The given formula to find the magnetic force is F_{ma}=BqV---(i)

The given formula to find the electric force is F_{el}=qE---(ii)

The velocity of electric field and magnetic field is said to be perpendicular

Electric field is equal to magnectic field

Equate equation (i) and equation (ii)

Bqv=qE\\\\v=\frac{E}{B}

v=\frac{187500}{0.125} \\\\v=15\times10^5m/s

It is said that the particles moves in semi circle, so we are going to consider using centripetal force

F_{ce}=\frac{mv^2}{r}---(iii)

magnectic field is equal to centripetal force

Lets equate equation (i) and (iii)

Bqr=\frac{mv^2}{r} \\\\\frac{q}{m}=\frac{v}{Br}  \\\\\frac{q}{m} =\frac{15\times 10^5}{0.125\times0.12525} \\\\=\frac{15\times10^5}{0.015656} \\\\=95808383.23\\\\=958.1\times10^5C/kg

Therefore,  the particle's charge-to-mass ratio is 958.1\times10^5C/kg

b)

To identify the particle

Then 1/ 958.1 × 10⁵ C/kg

The charge to mass ratio is very close to that of a proton, which is about 1*10^8 C/kg

Therefore the particle is proton.

8 0
4 years ago
How can humans building a drainage system affect the water cycle?
nasty-shy [4]
Human building a drainage system could affect the water cycle because : 
C. water would be directed to a new location because of the drains

This could potentially changed the natural occurrence that usually happened within the water cycle

hope this helps


5 0
3 years ago
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When entering an expressway, in the acceleration lane you should: A search for a gap in traffic and adjust your speed to the spe
sattari [20]

Answer:A

Explanation: search for a gap in traffic and adjust your speed to the speed of the traffic.

3 0
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