Ask question

Ask question

All categories

2 years ago

13

A planet has a period of revolution about the Sun equal to and a mean distance from the Sun equal to R .T^2 varies directly as _

_________.

1 answer:

shutvik [7]2 years ago

4 0

T² caries directly as R³ .

This is Kepler's 3rd law of planetary motion .

You might be interested in

It's time for Santa to deliver his presents. Assuming he delivers presents all over the world, he has to travel about 75,000,000

algol13

2,419,354.8387960000

5 0

2 years ago

5. How are humans affecting global climate change?

andreyandreev [35.5K]

Answer:

Due to the generation of carbon dioxide

Explanation:

Climate change occurs due to global warming generated by greenhouse gases. Carbon dioxide is the gas that does not leave or allow solar radiation from the sun to rise from the Earth's surface, increasing the average temperature of the planet.

Burning fossil fuels for energy generation such as coal is another source of carbon dioxide generation. The generation of energy should be directed towards the production of renewable energies, using sources such as solar and wind energy.

5 0

3 years ago

During the storm a tree fell over into a river what might happen to the tree

mart [117]

The tree might get swept away by the current and it will disappear when it catches on something

4 0

3 years ago

If you were trying to cross a river with the shortest possible time, would you aim your boat slightly upstream, directly across

Maru [420]

Slightly downstream for the shortest possible time

7 0

3 years ago

After a fall, a 90 kg rock climber finds himself dangling from the end of a rope that had been 16 m long and 7.8 mm in diameter

Nesterboy [21]

Explanation:

Given that,

Mass of the rock climber, m = 90 kg

Original length of the rock, L = 16 m

Diameter of the rope, d = 7.8 mm

Stretched length of the rope, $\Delta L=3.1\ cm$

(a) The change in length per unit original length is called strain. So,

$\text{strain}=\dfrac{\Delta L}{L}\\\\\text{strain}=\dfrac{3.1\times 10^{-2}}{16}\\\\\text{strain}=0.00193$

(b) The force acting per unit area is called stress.

$\text{stress}=\dfrac{mg}{A}\\\\\text{stress}=\dfrac{90\times 10}{\pi (3.9\times 10^{-3})^2}\\\\\text{stress}=1.88\times 10^7\ Pa$

(c) The ratio of stress to the strain is called Young's modulus. So,

$Y=\dfrac{\text{stress}}{\text{strain}}\\\\Y=\dfrac{1.88\times 10^7}{0.00193}\\\\Y=9.74\times 10^9\ N/m^2$

Hence, this is the required solution.

8 0

2 years ago