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2 years ago

10

Suppose you took a trip to the moon. Write a paragraph describing how and why your weight would change. Would your mass change t

oo?

1 answer:

noname [10]2 years ago

5 0

Your weight would change but not your mass, the moon has less gravity so therefore you are going to be lighter :-)

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A car is moving at a initial velocity of 20 meters per second accelerates at a rate of 1.5 meters per second squared for 4 secon

Brrunno [24]

Answered using calculus.
Antidifferentiated the acceleration to get velocity. Added variable c as we do not know if there was an extra number there yet.
Knowing that when time is 0, the velocity is 20, we can substitute those numbers into the equation and find that c = 20.
Now we have full velocity equation: v = 1.5t + 20
Now we substitute 4 into t to find out the velocity after 4 seconds. This gives us the final answer of 26m/s

5 0

3 years ago

A child of mass m is standing at the edge of a carousel. Both the carousel and the child are initially stationary. The carousel

suter [353]

Answer:

the angular velocity of the carousel after the child has started running =

$\frac{2F}{mR} \delta t$

Explanation:

Given that

the mass of the child = m

The radius of the disc = R

moment of inertia I = $\frac{1}{2} mR^2$

change in time = $\delta \ t$

By using the torque around the inertia ; we have:

T = I×∝

where

R×F = I × ∝

R×F = $\frac{1}{2} mR^2$ ∝

F = $\frac{1}{2} mR$ ∝

∝ = $\frac{2F}{mR}$ ( expression for angular angular acceleration)

The first equation of motion of rotating wheel can be expressed as :

$\omega = \omega_0 + \alpha \delta t$

where ;

∝ = $\frac{2F}{mR}$

Then;

$\omega = 0+ \frac{2F}{mR} \delta t$

$\omega = \frac{2F}{mR} \delta t$

∴ the angular velocity of the carousel after the child has started running =

$\frac{2F}{mR} \delta t$

7 0

3 years ago

Table C: Average Speeds for Lower Racetrack

Blababa [14]

Answer:

Centripetal Acceleration = v^2/r

= (circumference/time)^2/r

= (2*pi*r/t)²)/r

= ((2³.14*50/14.3)²)/50

= 9.64 m/s²

brainlist?

Explanation:

5 0

3 years ago

Oduvanchick [21]

The distance it traveled is 147

5 0

2 years ago

If the ultraviolet photon has a wavelength of 249 nm and one of the photons emitted by the fluorescent material has a wavelength

melamori03 [73]

Answer:

601 nm

Explanation:

Energy of photon having wavelength of λ nm

= $\frac{1244}{\lambda}$ eV

Energy of 249 nm photon

= $\frac{1244}{249}$

=4.996 eV

Similarly energy of 425nm photon

= $\frac{1244}{425}$

=2.927 eV

Difference = 2.069 eV.

This energy will give rise to another photon whose wavelength will be

λ = $\frac{1244}{2.069}$

= 601 nm.

6 0

3 years ago