Fire is actually a chemical reaction. It's an oxidation reaction to be specific. When wood gets hot enough (the part of the wood that is burning) the large hydrocarbons break down to charred solids and a gas. The gas is what reacts with oxygen in the atmosphere to produced light, CO2 and H2O.
One isomer is formed
1,1- Dichloroethane is the isomer.
If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, it would result in one isomer.
- In contrast to 1,2-dichloroethane, which has two chlorine atoms connected to distinct carbon atoms, 1,1-dichloroethane has two chlorine atoms bound to the same carbon atom.
- Isomers are each of two or more compounds having the same formula but various atom arrangements in the molecule and unique characteristics.
<h3>What three types of isomers are there?</h3>
- Chain isomers
- Functional group isomers
- Positional isomers
These are the three different categories of structural isomers.
<h3>How is an isomer recognized?</h3>
- Their bonding patterns and the way they occupy three-dimensional space can be used to distinguish them.
- Determine the bonding patterns of structural (constitutional) isomers.
- Although the atoms in the compounds are the same, their connections create various functional groups.
<h3>What makes isomers significant?</h3>
- Because two isomers might have the same chemical formula but different chemical structures, they are significant.
- The molecule's properties are influenced by its structure.
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Missing in your question Ka2 =6.3x10^-8
From this reaction:
H2SO3 + H2O ↔ H3O+ + HSO3-
by using the ICE table :
H2SO3 ↔ H3O + HSO3-
intial 0.6 0 0
change -X +X +X
Equ (0.6-X) X X
when Ka1 = [H3O+][HSO3-]/[H2SO3]
So by substitution:
1.5X10^-2 = (X*X) / (0.6-X) by solving this equation for X
∴ X = 0.088
∴[H2SO3] = 0.6 - 0.088 = 0.512
[HSO3-] = [H3O+] = 0.088
by using the ICE table 2:
HSO3- ↔ H3O + SO3-
initial 0.088 0.088 0
change -X +X +X
Equ (0.088-X) (0.088+X) X
Ka2= [H3O+] [SO3-] / [HSO3-]
we can assume [HSO3-] = 0.088 as the value of Ka2 is very small
6.3x10^-8 = (0.088+X)*X / 0.088
X^2 +0.088 X - 5.5x10^-9= 0 by solving this equation for X
∴X= 6.3x10^-8
∴[H3O+] = 0.088 + 6.3x10^-8
= 0.088 m ( because X is so small)
∴PH= -㏒[H3O+]
= -㏒ 0.088 = 1.06
Sucrose, a sweet, white crystalline substance, C12 H22 O11, OBTAINED CHIEFLY FROM THE JUICE OF THE SUGAR CANE AND SUGAR BEET, BUT ALSO PRESENT IN SORGHUM, THE sugar maple, some palms, and various other plants, and having extensive nutritional, pharmaceutical, and industrial uses; any of the class of carbohydrates to which this substance belongs, as glucose, levulose, and lactose.
