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dexar [7]
3 years ago
11

An acorn falls from a tree and accelerates at 9.8 m/s2. It hits the ground in 0.67 s. What is the speed of the acorn when it hit

s the ground?
Chemistry
1 answer:
ivolga24 [154]3 years ago
8 0
Acceleration means that while it's falling, its speed will increase by 9.8 m/s
every second.  That's the acceleration of everything that falls near the Earth's
surface, no matter how heavy or light the object is.

In 0.67 seconds, then, the speed of the acorn increases from zero to

                 (0.67 x 9.8) = <u>6.57 m/s</u> .
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Which statements describe an element? Check all that apply.
Molodets [167]

Answer:

<em>Hello, Your answer will be B,C,E, And F.</em>

Explanation:

An element is a substance whose atoms have same number of protons which means all atoms in an element have same atomic number. Elements are simplest substances which cannot be broken down by physical changes or chemical reactions. Elements are classified by their names and symbols. Hope That Helps!

8 0
3 years ago
3.95 g of sugar (C6H12O6) is dissolved in water to make 158 mL of solution. Find the molarity.
12345 [234]

Answer:

[C₆H₁₂O₆] = 0.139 M

Explanation:

Molarity si defined as a sort of concentration. It indicates the moles of solute that are contained in 1 L of solution.

We can also say, that molarity are the mmoles of solute contained in 1 mL of solution.

For this case, the solute is sugar (glucose). Let's determine M (mmol/mL)

(3.95 g . 1mol / 180g) . (1000 mmol / 1mol) / 158 mL

We determine moles, we convert them to mmoles, we divide by mL

M = 0.139 M

Moles = 3.95 g . 1mol / 180g → 0.0219 mol

We convert mL to L → 158 mL . 1L/1000mL = 0.158L

M = 0.0219 mol / 0.158L = 0.139 M

8 0
3 years ago
What technique would most likely be used to separate a solution with many
Flura [38]

Answer:A

Explanation:

3 0
3 years ago
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4 0
2 years ago
An unknown compound contains 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen by mass. A mass spectrometry analysis reveals that
tiny-mole [99]

Answer:

Molecular formula is C₂₆H₃₆O₄

Explanation:

The compound is 75.69 % C, 8.80 % H and 15.51 % O. This data means, that in 100 g of compound we have 75.69 g, 15.51 g and 8.80 g of, C, O and H, respectively. We know the molar mass of the compound, so we can work to solve the moles of each element.

In 100 g of compound we have 75.69 g C, 15.51 g O and 8.80 g H

In 412 g of compound we would have:

(412 . 75.69) / 100 = 311.8 of C

(412 . 15.51) / 100 = 63.9 g of O

(412 . 8.80) / 100 = 36.2 g of H

Now, we can determine the moles of each, that are contained in 1 mol of compound.

312 g / 12 g/mol 26 C

64 g / 16 g/mol = 4 O

36 g / 1 g/mol = 36 H

Molecular formula is C₂₆H₃₆O₄

4 0
3 years ago
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