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____ [38]
3 years ago
11

A solution was prepared by dissolving 31.0 g of kcl in 225 g of water. part a calculate the mass percent of kcl in the solution.

Chemistry
1 answer:
iragen [17]3 years ago
3 0
<span>Answer: Mass % KCL: Add the grams of both compounds (31.0 g KCL + 225 g water) to find total mass and then divide the grams of KCL over the total mass, then multiply by 100: ( 31.0 g KCL / 31.0 g + 225 G) * 100% Mole fraction KCL Calculate the moles of KCL and water and add them to find the total moles (Moles of KCL + moles of water). Then, divide the number of KCL moles over the total moles. moles of KCL/ moles kcl + moles water= mole fraction of KCL</span>
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Morgarella [4.7K]

Answer:

This metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

Explanation:

A pie of unknown metal presents a mass (M) of 348 g. This metal is heated using energy (E) of 6.64 kJ and the temperature increases from T1 =24.4 to T2 =43.6°C. We can calculate the specific heat (H) of this metal as follows

H = \frac{E}{M*(T2-T1)}

We can replace previously presented data in this equation. After simplifying and converting to adequated units, we found that

H = \frac{6640 J}{0.348 Kg*(43.6-24.4) C} =\frac{6640 J}{6.686 KgC}

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H = 993 \frac{J}{kgC}

The aluminium could be the metal, its specific heat is similar to that found in this problem.

Finally,  we can conclude that this metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

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Electrons are emitted from the surface of a metal in photoelectric effect.

<h3>What is the photoelectric effect?</h3>

The photoelectric effect is the emission of electron from the surface of a metal when light is shone on the surface..

For electrons to be emitted, the light must have a certain frequency known as threshhold frequency.

Therefore, electrons are emitted from the surface of a metal in photoelectric effect.

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