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3 years ago

A solution was prepared by dissolving 31.0 g of kcl in 225 g of water. part a calculate the mass percent of kcl in the solution.

1 answer:

3 0

<span>Answer: Mass % KCL: Add the grams of both compounds (31.0 g KCL + 225 g water) to find total mass and then divide the grams of KCL over the total mass, then multiply by 100: ( 31.0 g KCL / 31.0 g + 225 G) * 100% Mole fraction KCL Calculate the moles of KCL and water and add them to find the total moles (Moles of KCL + moles of water). Then, divide the number of KCL moles over the total moles. moles of KCL/ moles kcl + moles water= mole fraction of KCL</span>

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For the reaction below, initially the partial pressure of all 3 gases is 1.0atm. . 2NH3(g)--> N2(g) + 3H2(g) K, 0.83 1. When

erma4kov [3.2K]

Answer:

The reaction would shift toward the reactants

When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm

Explanation:

For the reaction:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where K is defined as:

$K = \frac{P_{N_{2}}*P_{H_2}^3}{P_{NH_3}^2} = 0.83$

As initial pressures of all 3 gases is 1.0atm, reaction quotient, Q, is:

$Q = \frac{1atm*{1atm}^3}{1atm^2} = 1$

As Q > K, <em>the reaction will produce more NH₃ until Q = K consuming N₂ and H₂.</em>

Thus, there are true:

<h3>The reaction would shift toward the reactants</h3><h3>When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm</h3>

<em />

4 0

3 years ago

What is the sequence of coefficients that will balance the following decomposition reaction of dihydrogen monosulfide? H₂S ----&

RUDIKE [14]

8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

Answer:

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 2 H and 1 S

Right side: 2 H and 8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

8 H₂S → H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8

Right side: 2 H and 8 S

Now you need to start balancing the hydrogen to get the same amount from each side of the reaction. So:

8 H₂S → 8 H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8

Right side: 16 H and 8 S

<u><em>The balanced reaction is:</em></u>

3 0

2 years ago

Use the periodic table to identify each of the following bonds as polar or nonpolar.

Molodets [167]

Answer:

Polar

Step-by-step explanation:

Electronegativity increases from <em>left to right</em> in the Periodic Table.

Cl is further right than C (both tinted pink) in the portion of the Periodic Table below.

Cl is <em>more electronegative</em> than C, so the Cl has a partial negative charge and the C has a partial positive charge.

The C-Cl bond is polar.

5 0

3 years ago

A solution is prepared by dissolving 0.23 mol of chloroacetic acid and 0.27 mol of sodium chloroacetate in water sufficient to y

Sergio [31]

Answer:

c. chloroacetate ion

Explanation:

The chloroacetic acid, ClCH₂CO₂H, is a weak acid with Ka = 1.36x10⁻³. When this weak acid is in solution with its conjugate base, ClCH₂CO₂⁻ (From sodium chloroacetate) a buffer is produced. The addition of a strong acid as the HCl produce the following reaction

HCl + ClCH₂CO₂⁻ → ClCH₂CO₂H + Cl⁻.

Where the acid reacts with the chloroacetate ion to produce more chloroacetic acid

That means, the HCl reacts with the chloroacetate ion present in the buffer solution

Right answer is:

<h3>c. chloroacetate ion</h3>

8 0

2 years ago

What is a example of soda ash

lesya [120]

used in the manufacturing of glass, detergents chemicals and other industrial products.

4 0

3 years ago