The balanced chemical reaction is written as :
Na2CO3<span> + 2HCl === 2NaCl + H2O + CO2
</span>
We are given the amount of NaCl to be produced from the reaction. This will be the starting point for the calculations. We do as follows:
120 g NaCl ( 1 mol / 58.44 g) ( 1 mol Na2CO3 / 2 mol NaCl)( 105.99 g / 1 mol ) = 1108.82 g Na2CO3 needed
Explanation:
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Answer:
10.4376 g
Explanation:
First we <u>calculate the sum of the weighings</u>:
- 10.4375 g + 10.4381 g + 10.4373 g + 10.4376 g = 41.7505 g
Then we <u>divide the sum by the number of weighings to calculate the average:</u>
- Average = Sum of weighings / Number of weighings
- 41.7505 g / 4 = 10.4376 g
