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2 years ago

15

1.) __ N2 + H2 --------->_NH3

1 answer:

kykrilka [37]2 years ago

8 0

Answer:

N2 + 3H2 ------> 2NH3

2AlBr + 3K2SO4------> 6KBr + Al(SO4)3

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How much mass does 4.53 x 10^22 have

snow_tiger [21]

<span>4.53<span>x^<span>10^22</span></span></span>Simplifies to:<span>4.53x</span><span>=<span>4.53*x</span></span><span>=<span>4.53<span>x</span></span></span>

8 0

3 years ago

Virty [35]

Answer:

A. the charge on their ions

Explanation:

Elements are grouped into the same group in the periodic table if they have the same valence electrons. However, the number of valence electrons an element has, determines the number of charges it can possess.

According to this question, two elements in the same group of the periodic table will have the same charge on their ions because they both have the same number of valence electrons.

5 0

3 years ago

The average molecular weight for element X is 59.97 g/mol. There are two known isotopes of element X, one weighing 59 g/mol, and

Temka [501]

Answer:

The correct answer is:48.5% X-59, 51.5% X-61

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of X-59 isotope be 'x'. So, fractional abundance of X-61 isotope will be '1 - x'

For X-59 isotope:

Mass of X-59 isotope =59 g/mol

Fractional abundance of X-59 isotope = x

For X-61 isotope:

Mass of X-61 isotope = 61 g/mol

Fractional abundance of X-61 isotope = 1 - x

Average atomic mass of chlorine = 35.4527 amu

Putting values in equation 1, we get:

$59.97 g/mol=[(59 g/mol\times x)+(61 g/mol\times (1-x))]\\\\x=0.515$

Percentage abundance of X-59 isotope = $0.515\times 100=51.5\%$

Percentage abundance of X-61 isotope = $(1-0.515)=0.485\times 100=48.5\%$

Hence, the percentage abundance of both the isotopes X-59and X-61 are 51.5% and 48.5% respectively.

4 0

3 years ago

Which of these elements is the most electronegative? <br> A. Sr<br> B. Na<br> C. Li<br> D. Ba

hoa [83]

Answer:

A. SR

Explanation:

SR is strongtium and is an electronegative element:))

hope this helps:))

6 0

3 years ago

Read 2 more answers

The second-order decomposition of NO2 has a rate constant of 0.255 M-15-1. How much NO2 decomposes in 4.00 s if the initial conc

S_A_V [24]

Answer:

Option D, Concentration of NO2 decomposes after 4.00 s = 0.77 mol

Explanation:

$rate\;constant = 0.255\;M^{-1}s{-1}$

Time (t) = 4.00\;s

Initial concentration of NO2 = 1.33 M

Integrated law for second order reaction:

$\frac{1}{[A]}=\frac{1}{[A]_0} =kt$

Where, [A] = Concentration after time, t

[A]0 = Intitial concentration, k = rate constant, t = time

On substituting values in the above

$\frac{1}{[A]}=\frac{1}{1.33} =0.255 \times 4.00$

$\frac{1}{[A]} =1.772$

[A] = 0.5644 M

Concentration of NO2 decomposes after 4.00 s = 1.33 - 0.5644 = 0.7656 M

No. of mole = Molarity * volume

= 0.7656 * 1

= 0.7656 mol 0r 0.77 mol

4 0

4 years ago