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NNADVOKAT [17]
3 years ago
14

Write the ratio as a fraction in simplest form a/b. What is the ratio of baseballs to basketballs?

Mathematics
1 answer:
Olin [163]3 years ago
7 0
The ratio of baseballs to basketballs is

baseball: basketballs, or 

baseballs/basketballs

if you give me the numbers i can plug it in


hope this helps
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The answer is the Parallelogram
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There is a sales tax of $6 on an item that costs $64 before tax. The sales tax on a second item is $8.25 . How much does the sec
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The second item would be $88 before tax since the tax rate is <span>9.375%</span>
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Figure A is a scale image of Figure B. What is the value of x?
Arte-miy333 [17]
X=30
Put in proportions x/45 = 18/27.
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3 years ago
Magaldi is constructing its cash budget. Its budgeted monthly sales are $20,000, and they are constant from month to month. 60%
iogann1982 [59]

Answer:

$5,820

Step-by-step explanation:

The average net cash flow during the month is total cash receipt minus total payments.

Cash receipt on the month's sales=60%*$20,000*98.5%=$11820

60% cash received ,the 98.5% is after cash discount of 1.5%

cash receipt from previous month sale=40%*$20,000=$8,000

Payment for purchases=$20,000*40%=$8,000

payment for wages,rent and taxes=$20,000*30%=$6000

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total cash outflow=$8,000+$6,000=$14,000

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5 0
3 years ago
Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
  • Equally as likely to be a boy or a girl, hence p = 0.5.

The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0
3 years ago
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