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nataly862011 [7]
3 years ago
9

What is the distance between (4,-7) and (-5, -7)?

Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

Step-by-step explanation:

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Four time a number r plus half a number s equals 12. Twice the number r plus one fourth of the numbers s equals 8. What are the
Snezhnost [94]

The system of equations have no solution.

Explanation:

The equations are 4r+\frac{1}{2}s=12 and 2r+\frac{1}{4} s=8

To find the two numbers, let us solve the equations using substitution method.

From the equation 2r+\frac{1}{4} s=8, let us determine the value of r,

$\begin{aligned} 2 r+\frac{1}{4} s &=8 \\ 2 r &=8-\frac{1}{4} s \\ r &=\frac{1}{2}\left(8-\frac{1}{4} s\right) \\ r &=4-\frac{1}{8} s \end{aligned}$

Let us substitute the value of r in 4r+\frac{1}{2}s=12, we get,

$\begin{aligned} 4\left(4-\frac{1}{8} s\right)+\frac{1}{2} s &=12 \\ 16-\frac{1}{2} s+\frac{1}{2} s &=12 \\ 16 &=12 \end{aligned}$

which is not possible.

This means that the system has no solution.

6 0
3 years ago
Plzzzzzzzzzzzzzzzz help meeeeeeeeeeeeeeeeeeeeee if u do ill give u a dollar
myrzilka [38]

Answer:

B

x is the price of the sweater so 3x  and add $15 for the skirt which would add up to $90

6 0
3 years ago
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Toby pulled weeds and earned $22.50 for three hours of work. How much will he earn tomorrow if he works for 2 hours?
postnew [5]
How many hours total?
8 0
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Every 3 weeks 8 students will lose their metro cards... How many will lose it in 9 weeks
Marina86 [1]
First we must divide 9 by 3.

9/3 = 3

Then multiply it by 8

3*8 = 24. Hope this helps!

7 0
3 years ago
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Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

du=dx         v=2\cdot{e^(2x)}

\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du

\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx

\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C

We can therefore determine that if x tends to 0 the limit is -1

\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1

5 0
3 years ago
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