<h3>Given</h3>
Two positive numbers x and y such that xy = 192
<h3>Find</h3>
The values that minimize x + 3y
<h3>Solution</h3>
y = 192/x . . . . . solve for y
f(x) = x + 3y
f(x) = x + 3(192/x) . . . . . the function we want to minimize
We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.
... f'(x) = 1 - 576/x² = 0
... 576 = x² . . . . . . . . . . . . multiply by x², add 576
... √576 = x = 24 . . . . . . . take the square root
... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y
The first number is 24.
The second number is 8.
2x3= 6
18÷6= 3
So, 3x4 = 12
Convert -6 1/8 to an improper fraction: -49/8
7(-49/8) = -343/8 = -42.875 = -42 7/8
Answer:
To find the mean you must add up all the numbers you have together and then divide the buy the amount of numbers you added. When you add these numbers up you get 30, and we have 5 numbers here, when we divide 30 by 5 we get 6. So, Tara is correct in saying that the mean is 6.
Step-by-step explanation:
