Notice the picture below
negative angles, are just angles that go "clockwise", namely, the same direction a clock hands move hmmm so....  and one revolution is just 2π
now, you can have angles bigger than 2π of course, by simply keep going around, so, if you go around 3 times on the circle, say "counter-clockwise", or from right-to-left, counter as a clock goes, 3 times or 3 revolutions will give you an angle of 6π, because 2π+2π+2π is 6π
now... say... you have this angle here... let us find another that lands on that same spot
by simply just add 2π to it :)  

now, that's a positive one
and  

to get more, just keep on subtracting or adding 2π
 
        
        
        
 Answer:
nothing there
Step-by-step explanation:
help with what
 
        
                    
             
        
        
        
N/3 if thats what your looking for
        
             
        
        
        
Answer:

Step-by-step explanation:
![\sf f(x) = 9x-10\\\\Put\ x = 8\\\\f(8) = 9(8) -10\\\\f(8) = 72-10\\\\f(8) = 62\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20f%28x%29%20%3D%209x-10%5C%5C%5C%5CPut%5C%20x%20%3D%208%5C%5C%5C%5Cf%288%29%20%3D%209%288%29%20-10%5C%5C%5C%5Cf%288%29%20%3D%2072-10%5C%5C%5C%5Cf%288%29%20%3D%2062%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>
 
        
                    
             
        
        
        
Given a right triangle with the side lengths of legs = 9 and 13
For the required angle :
opposite side = 9
adjacent side = 13
so, 
