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3 years ago

Meandre has 8 pints of milk. If he drinks ¼ of a pint of milk each day, how long will the 8 pints of milk last him?

Mathematics

2 answers:

AVprozaik [17]3 years ago

8 0

Answer:z

Step-by-step explanation:

Lelu [443]3 years ago

5 0

Answer:

Step-by-step explanation:

1/4 = 0.25

8 divied 32

<u><em>In multiplacation</em></u>

8 time 4 = 32

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What is x 35x+10=190

Aneli [31]

Answer:

Step-by-step explanation:

35x + 10 = 190

35x = 190 - 10

35x = 180

x = 180 / 35

Therefore x = 5.14

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3 years ago

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The polynomial below is a perfect square trinomial of the form A^2-2AB+B^2. 9x^2-18x+36

baherus [9]

No, It's not.

coefficients for perfect square would be:
3² - 2(3)(6) + 6² = 9 - 36 + 36

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3 years ago

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Number 21 please and thank you

olga2289 [7]

Answer:

$\frac{5}{6}$

Step-by-step explanation:

sin =opposite/hypotenuse

sinQ=5/6

7 0

2 years ago

Mr. Roundtree had 20 tickets. He gave 10 to his family and 8 to his friends.

Ket [755]

He has two tickets left

5 0

3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

2 years ago