<span>Orthocenter is at (-3,3)
The orthocenter of a triangle is the intersection of the three heights of the triangle (a line passing through a vertex of the triangle that's perpendicular to the opposite side from the vertex. Those 3 lines should intersect at the same point and that point may be either inside or outside of the triangle. So, let's calculate the 3 lines (we could get by with just 2 of them, but the 3rd line acts as a nice cross check to make certain we didn't do any mistakes.)
Slope XY = (3 - 3)/(-3 - 1) = 0/-4 = 0
Ick. XY is a completely horizontal line and it's perpendicular will be a complete vertical line with a slope of infinity. But that's enough to tell us that the orthocenter will have the same x-coordinate value as vertex Z which is -3.
Slope XZ = (3 - 0)/(-3 - (-3)) = 3/0
Another ick. This slope is completely vertical. So the perpendicular will be complete horizontal with a slope of 0 and will have the same y-coordinate value as vertex Y which is 3.
So the orthocenter is at (-3,3).</span>
Answer:
Equation simplifed= 8x^2-14x-15
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The rulers tell you the length of the sides
The range is a set of elements from the second set.
Therefore your answer is:
<h3>D. { -4, 1, 7, 15 }</h3>
10. B
11. D
12. C
13. B
14. B
15. D