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emmasim [6.3K]
3 years ago
15

What is the solution of the equation x^2 + 6x + 6 = 0?

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0
I hope it will help you.

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38 kg of onions cost $144.40. how much would 49 kg cost?
Lerok [7]

Answer:

$186.2

Step-by-step explanation:

   38 kg costs $144.40

∴ 1 kg costs = \frac{144.40}{38}  = $3.8

   49 kg costs = 3.8  x  49

                        = $186.2

7 0
1 year ago
Read 2 more answers
Which side lengths form a right triangle?Choose all answers that apply: (Choice A) 2 , 1 5 , 1 7 Choice B) 1 , 8 , square root o
iren [92.7K]

Answer:

B, but I can't read C

Step-by-step explanation:

the sum of any 2 sides must be longer that the 3rd.

A is not correct, 2 + 15=17, needs to be greater.

B 1, 8, 8.1 so yes as 1+8 >8.1

C 2, 8.9, I cna't tell if that last number is 9 or 92?

6 0
3 years ago
The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th
12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = \dfrac{2400 \ cm^2}{p}

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be \dfrac{2400 \ cm^2}{p} + 20

The area of the printed material can now be:  A = (p+30)(\dfrac{2400 }{p} + 20)

=2400 +20 p +\dfrac{72000}{p}+600

Let differentiate with respect to p; we have

\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}

Also;

\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}

For the smallest area \dfrac{dA}{dp }=0

20 - \dfrac{72000}{p^2}=0

p^2 = \dfrac{72000}{20}

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression  q = \dfrac{2400 \ cm^2}{p}   to solve for q;

q = \dfrac{2400 \ cm^2}{p}

q = \dfrac{2400 \ cm^2}{60}

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = \dfrac{2400 \ cm^2}{p} + 20 = \dfrac{2400 \ cm^2}{60} + 20  = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

4 0
3 years ago
PLEASE HELP ME!!!!!!!
Shalnov [3]

Answer:

i6 sqrt 5

Step-by-step explanation:

It cannot be 12i sqrt 5 as this is 26.8326....

it cannot be  18i sqrt 5 as this is 40.249...

It cannot be 8i sqrt 5 as this is 17.888....

It cnanot be 8i sq rt 10 as this is 25.298....

i6 sq rt 5 = sqrt -180

6 0
2 years ago
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An mp3 player has 12 songs on shuffle. how many different orders can the songs play
4vir4ik [10]
144 ways because 12 songs 12 ways 12*12
8 0
3 years ago
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