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Greeley [361]
3 years ago
12

Please solve this question withvfull process i will wark as braineast a) After allowing 5 % discount on the marked price of a ra

dio 10 % VAT is charged on it, then its
price became Rs 1,672. How much amount was given in the discount?​
Mathematics
1 answer:
schepotkina [342]3 years ago
7 0

Answer:

Let the marked price be x

Discount % = 10%

Discount = 10\% \times x = 0.1x10%×x=0.1x

Cost after discount = x-0.1x = 0.9x

10%vat is charged on it

Cost including VAT = 0.9x+0.1(0.9x)=0.99x0.9x+0.1(0.9x)=0.99x

We are given that  it's price became rs 1672

So, 0.99x = 1672

x=\frac{1672}{0.99}x=0.991672

x=1688.88

Discount = 0.1x=0.1(1688.88)=168.888

Hence The discount

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Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

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2 years ago
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How many revolutions would a wheel of radius 2m make to travel 1km
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\dfrac{ 1000 \textrm{ meters}}{2\pi(2) \textrm{ meters per rev}} \approx 79.577 \textrm{ revs}


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4 years ago
Simplify the algebraic expression:<br><br> 5(x + 2) + 2(x - 3)
aliya0001 [1]

Answer:

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Step-by-step explanation:

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3 years ago
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Marizza181 [45]
35 kilometers in 7 hours would be 7/35 which is 5 kilometers an hour, in 3 hours it would be 15 kilometers
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BRAINLIEST, 40 points
ollegr [7]

Answer:

A

Step-by-step explanation:

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