Answer:
Step-by-step explanation:
I have no idea what formula that is you're using but the one I teach in both algebra 2 and in precalculus for continuous compounding is
where A(t) is the amount after the compounding, P is the initial investment, ee is Euler's number, r is the interest rate in decimal form, and t is the time in years. If our money doubles, we just have to come up with a number which will be P and then double it to get A(t). It doesn't matter what number we pick to double, the answer will come out the same regardless. I started with 2 and then doubled it to 4 and filled in the rest of the info given with time as my unknown:
Begin by dividing both sides by 2 to get
The only way we can get that t out of its current position is to take the natural log of both sides. Natural logs have a base of e, so
This is because they are inverses of one another. Taking the natural log of both sides:
Now divide by .062 to get
t = 11.2 years
The question is "What is the scale of the model to the actual statue"
That means you must put 2/15.
2 being the model
15 being the actual statue
Take that fraction and equal is to 1/x.
Multiply 15 to 1 and 2 to x.
In the end, to solve, you divide 15 by 2x.
The answer is X=7.5
1 : 7.5
Answer:
b. is the right answer of your question
Answer:
3 1/3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Exact Form:
x
=
10
/3
Decimal Form:
x
=
3.
3
3
Mixed Number Form:
x = 3 1/3
Answer:
Step-by-step explanation:
a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.
b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).
c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following
where 
