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ycow [4]
3 years ago
15

Determine whether the given value is a solution of the equation.

Mathematics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

16 is not the solution to the equation

Step-by-step explanation:

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Is there a difference in the amount of airborne bacteria between carpeted and uncarpeted rooms? In an experiment, seven rooms we
Annette [7]

Answer:

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Step-by-step explanation:

A. There are outliers in these data, so we can't rely on the two-sample t test.

There are no outliers, as the seven rooms for both sample have similar size and function.

B. This test is unreliable because the populations we're sampling from are heavily skewed.

We don't know if the populations are heavily skewed, but this effect should be appeased by the sampling.

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Correct conclusion, as the P-value is surely greater than the significance level (usually 0.10 at most).

D. There is fairly strong evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

There is no evidence as the P-value is greater than the significance level.

4 0
3 years ago
Work out the surface area of the solid cuboid.<br> 3cm<br> 4cm<br> 5cm
Zarrin [17]

Answer: 94 cm^3.

Step-by-step explanation: You use the formula 2(ab+bc+ca). You plug in 3, 4, and 5 to get 94.

4 0
2 years ago
Read 2 more answers
Help based offf order of operations please help
JulijaS [17]

Answer:

The answer for :

h. \:  \:   \: \frac{5}{6}

i. \:  \:  \:  \frac{35}{32}

k. \:  \:  \:  \frac{-29}{20}

l. \:  \:  \:  \frac{13}{15}

Step-by-step explanation:

Question h:

\frac{2}{3}  + ( \frac{1}{3}  \times  \frac{1}{2} )

=  \frac{2}{3}  +  \frac{1}{6}

=  \frac{2 \times 2}{3 \times 2}  +  \frac{1}{6}

=  \frac{4}{6}  +  \frac{1}{6}

=  \frac{5}{6}

Question i:

\frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3}{2}  -  \frac{5}{8} )

=  \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3 \times 4}{2 \times 4}  -  \frac{5}{8} )

= \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{12}{8}  -  \frac{5}{8} )

=  \frac{7}{8}  +  (\frac{1}{4}  \times  \frac{7}{8} )

=  \frac{7}{8}  +  \frac{7}{32}

=  \frac{7  \times 4}{8 \times 4}  +  \frac{7}{32}

=  \frac{28}{32}  +  \frac{7}{32}

=  \frac{35}{32}

Question k:

\frac{3}{4}  - ( \frac{12}{7}  \div  \frac{12}{21} ) +  \frac{4}{5}

=  \frac{3}{4}  - ( \frac{12}{7}  \times  \frac{21}{12} ) +  \frac{4}{5}

=  \frac{3}{4}  -  \frac{3}{1}  +  \frac{4}{5}

= \frac{3 \times 5}{4 \times 5}  -  \frac{3 \times 20}{1 \times 20} +  \frac{4 \times 4}{5 \times 4}

=  \frac{15}{20}   -   \frac{60}{20} +  \frac{16}{20}

=  -  \frac{29}{20}

Question l:

\frac{5}{2}  \times ( \frac{2}{3}  -  \frac{1}{5} ) - ( \frac{2}{5}  \div  \frac{4}{3} )

=  \frac{5}{2}  \times ( \frac{2 \times 5}{3 \times 5}  -  \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5}  \times  \frac{3}{4} )

=  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{3}{15} ) -  \frac{3}{10}

=  (\frac{5}{2} \times   \frac{7}{15}) -  \frac{3}{10}

=  \frac{7}{6}  -  \frac{3}{10}

=  \frac{7 \times 5}{6 \times 5}  -  \frac{3 \times 3}{10 \times 3}

=  \frac{35}{30}  -  \frac{9}{30}

=  \frac{26}{30}

=  \frac{13}{15}

8 0
3 years ago
Which expression is equivalent to 6(x – 4)?<br> 0 -6x + 4<br> o 6x - 4<br> 0 6x - 24<br> 0 -6x + 24
Anika [276]

Answer:

6x-24

Step-by-step explanation:

The 6 multiplies each part in the parenthesis. So 6 * x = 6x and 6 * -4 = -24

5 0
3 years ago
11) Solve the equation<br> 6y+11=23<br><br> 12) Expand<br> 5(x-11)
Yakvenalex [24]
6y+11=23
     -11 -11
6y=12
/6    /6
y=2

5x-55
7 0
2 years ago
Read 2 more answers
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