D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
<span>2-EB=EA E midpoint of AB </span>
<span>DB=DC D midpoint BC ...............> ED=AC/2=2 </span>
<span>3-T midpoint of SR </span>
<span>U midpoint of QR ---------> TU = QS/2 </span>
<span>QS=2 TU = 4.4 </span>
<span>4- The same steps SR=2 UV=9 </span>
<span>5-N midpoint of KM </span>
<span>O midpoint of ML </span>
<span>* NO parallel to Kl</span>
Answer:
28 percent off is the answer :)
Step-by-step explanation:
Answer:
38.1 cm²
Step-by-step explanation:
area of full circle = π6² = 113.04 cm²
area of 150° segment = (150/360)(113.04) = 47.1 cm²
triangle base = sin 75° x 6 x 2 = 11.59
triangle height = cos 75° x 6 = 1.553
area of triangle = 1/2(11.59)(1.553) = 9 cm²
150° segment - triangle = 47.1 - 9 = 38.1 cm²
Hey, can you please fix this question? I can't seem to understand it. When you do, please tell me so I can help you out!
Answer:
<em>Hello bakugo here!</em>
Step-by-step explanation:
I don't see anything, is there supposed to be anything here? if not
<em>Thank you extra for FREE points! :D</em>
